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Bell Work: Simplify (-2) 4. Answer:16 Lesson 37: Areas of combined polygons.

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Presentation on theme: "Bell Work: Simplify (-2) 4. Answer:16 Lesson 37: Areas of combined polygons."— Presentation transcript:

1 Bell Work: Simplify (-2) 4

2 Answer:16

3 Lesson 37: Areas of combined polygons

4 The areas of some polygons can be found by dividing the polygon into smaller parts and finding the area of each part.

5 Formulas to be familiar with: Area of rectangle: length x width Area of triangle: ½ base x height Pythagorean Theorem: a + b = c 222

6 Example: Find the area of this figure. 4 cm 8cm 6 cm

7 Answer: Area of rectangle = 24 cm Area of triangle = 4 cm Area of polygon = 28 cm 2 2 2

8 Example: Use a calculator to estimate the area of this lot. 100 ft 110 ft 60 ft

9 Answer: x + 100 = 110 ≈ 46 Area of triangle ≈ 2300 ft Area of rectangle = 6000 ft Area of lot = 8300 ft 2 2 2 2 2 2

10 Example: In the figure, AD is 40 cm and DC is 30 cm. Point B is the midpoint of AC and Point E is the midpoint of AD. Find the perimeter and the area of the quadrilateral BCDE. ____ A B C D E

11 Answer: Area of figure BCDE = 450 cm 2

12 HW: Lesson 37 #1-30


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