1. DIMENSIONAL ANALYSIS (also known as Factor-Label Method)

2. Steps to Problem Solving Read problem Read problem Identify data Identify data Make a unit plan from the initial unit to the desired unit Make a unit plan from the initial unit to the desired unit Select conversion factors Select conversion factors Change initial unit to desired unit Change initial unit to desired unit Cancel units and check Cancel units and check Do math on calculator Do math on calculator Give an answer using significant figures Give an answer using significant figures

3. Conversions If you know ONE conversion for each type of measurement, you can convert anything! If you know ONE conversion for each type of measurement, you can convert anything! You must memorize and be able to use the metric conversions: You must memorize and be able to use the metric conversions:

4. Conversion Factors Fractions in which the numerator and denominator are EQUAL quantities expressed in different units Example: 1 ft = 12 in. Factors: 1 ft. and 12 in 12 in 1 ft. Example: 1 g = 10 2 cg. Factors: 1 g. and 10 2 cg 10 2 cg 1 g

5. How many minutes are in 2.5 hours ? Conversion factor 2.5 hr x 60 min = 150 min 1 hr 1 hr By using dimensional analysis / factor-label method, the UNITS ensure that you have the conversion right side up, and the UNITS are calculated as well as the numbers!

6. Sample Problem You have $7.25 in your pocket in quarters. How many quarters do you have? You have $7.25 in your pocket in quarters. How many quarters do you have? 7.25 dollars 4 quarters 1 dollar 1 dollar X = 29 quarters

7. Sample Problem – Using Metric You have 200 L of gasoline in your car. How many milliliters do you have? You have 200 L of gasoline in your car. How many milliliters do you have? 200 liters 10 3 milliliters 1 liter 1 liter = 2 x 10 3 mL

8. Learning Check SET UP THESE PROBLEMS USING DA - 2.22 cg = _______g 1.7 x 10 6 ng = ___________ g.288 g = __________mg 1.5 KL = ___________L

9. Multi-Step Problems You are in Paris and want some peaches for lunch. The sign in the fruit stand indicates that peaches are 11.5 francs per kilogram. Given that there are approximately 5 francs to the dollar, calculate what a pound of peaches will cost in dollars. 1 lb. 455 g 1000 g 1Kg11.5 f 1Kg5 f 1 $NOW WHAT? ?

10. Practice Problems Mrs. Borden has 3 classes of Chemistry. Each class has 25 students in it and they are each required to pay $15.00 for their lab fee. How much money will she have at the end of the semester if everyone pays their fee? Students in chemistry are required to write 10 lab reports per year. Each lab report has 6 sections each. Mrs. Borden requires that each section consists of a paragraph with no less than 7 sentences. How many paragraphs will each student write in 1 year time?

11. Complex Units Many times a problem will ask for you to convert 2 different units in one problem. Example: Change miles per hour to feet per minute. Given 20 miles per hour, how many feet is that per minute? ( 5280 ft = 1 mile) 20 miles 1 hour 60 min.1 mile 5280 ft. =1760 ft./min.

12. YOU TRY IT The density of gold is 19.3 g/mL. What is gold’s density in decigrams per liter?

13. NEW UNITS These are units you have never used but you must know for the rest of the year. 1 mole of any element or compound = its mass 1 mole of any element or compound = 6.02 x 10 23 representative particles

14. CONVERSION FACTORS 1 mole of NaCl = mass of NaCl How to calculate mass, using the periodic table: Na = 23.0 g and Cl = 35.5 g 23.0 + 35.5therefore 1 mole of NaCl = 58.5 g 58.5 g or 1 mole of NaCl 58.5 g

15. Practice pROBLEM You are given 3.5 moles of NaCl, how many grams of NaCl do you have? 3.5 moles NaCl 1 mole NaCl 58.5 g NaCl = 204.75 g of NaCl

16. CONVERSION FACTORS 1 mole of NaCl = 6.02 x 10 23 particles of NaCl Nothing to calculate, the number of particles is the same for every element therefore 1 mole of NaCl = 6.02 x 10 23 Particles or 1 mole of NaCl 6.20 x 10 23 particles

17. Practice pROBLEM You are given 3.5 moles of NaCl, how many particles of NaCl do you have? 3.5 moles NaCl 1 mole NaCl 6.20 x 10 23 particles of NaCl = 21.07 x 10 23 particles of NaCl or 2.107 x 10 24 particles

18. Multi-Step Problems You are given 4.55 x 10 25 particles of oxygen, how many grams of oxygen do you have? 4.55 x 10 25 rp of O 6.02 x 10 23 rp1 mole of O 16.0 g of O = 12.09 x 10 2 grams of O or 1.209 x 10 3 grams of O