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Coin Problems
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Example 1 A collection of nickels and dimes is worth $3.95. There are 8 more dimes than nickels. How many dimes and how many nickels are there? Let n be the number of nickels. Let d be the number of dimes. 0.05n d = 3.95 d = 8 + n d = 8 + n 0.05n (8 + n) = 3.95 d = 0.05n n = 3.95 d = 29 5n n = 395 21 nickels n = 395 29 dimes 15n = 315 n = 21
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Example 2 Rob has $2.85 in nickels and dimes. He has twelve more nickels than dimes. How many of each coin does he have?
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Example 3 Sally has 20 coins in her piggy bank, all dimes and quarters. The total amount of money is $3.05. How many of each coin does she have?
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