1. Solving Equations by Multiplying or Dividing
PRE-ALGEBRA LESSON 2-6
(For help, go to Lesson 1-9.)
Simplify each quotient.
1. 2.
3. 4. 18 21
–21 –7 7
–13
Check Skills You’ll Need
2-6

2. Solving Equations by Multiplying or Dividing
PRE-ALGEBRA LESSON 2-6
Solutions
= = –1
= – = 1 18 21
–21 –7 7
–13
2-6

3. Solving Equations by Multiplying or Dividing
PRE-ALGEBRA LESSON 2-6
Vocabulary
Vocabulary and Concepts
Division Property of Equality
You can divide the same number from each side of an equation
Arithmetic
Algebra
6 = 3( 2 ) If a = b and c = 0
6 = 3( 2 ) a = b
3 ____ c ___ 3 c
2-6

4. Solving Equations by Multiplying or Dividing
PRE-ALGEBRA LESSON 2-6
Vocabulary
Vocabulary and Concepts
Multiplication Property of Equality
You can multiply the same number from each side of an equation
Arithmetic
Algebra
12 = 3( 4 ) If a = b
= 3( 4 ) _____ then ac = _____ 2 bc
2-6

5. Solving Equations by Multiplying or Dividing
PRE-ALGEBRA LESSON 2-6
288 pens are boxed by the dozen. How many boxes are needed?
Let
Equation
288 = b
number of pens
Words
times
number of boxes. is 12
number of boxes •
2-6

6. Solving Equations by Multiplying or Dividing
PRE-ALGEBRA LESSON 2-6
(continued)
288 = 12b
Divide each side by 12.
288 12
12b =
24 = b Simplify.
24 boxes are needed.
Check  Is the answer reasonable?
Twelve times the number of boxes is the number of pens.
Since 12  24 = 288, the answer is reasonable.
Quick Check
2-6

7. Solving Equations by Multiplying or Dividing
PRE-ALGEBRA LESSON 2-6
Solve –2v = –24.
–2v = –24
Divide each side by –2.
–2v –2
–24 =
v = Simplify.
Check –2v = –24
–2 • (12) – Replace v with 12.
–24 = –24
Quick Check
2-6

8. Solving Equations by Multiplying or Dividing
PRE-ALGEBRA LESSON 2-6
Solve = – 5. x 8
= – 5 x 8 x 8
8 = 8(–5) Multiply each side by 8.
x = – 40 Simplify.
Quick Check
2-6

9. Solving Equations by Multiplying or Dividing
PRE-ALGEBRA LESSON 2-6
Solve each equation.
1. 4x = = 7y
3. -3b = = 10 = 21 13 r –5 -8
–50 t 20
–600
2-6