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LESSON 7-1 I can determine whether a dilation is an enlargement, a reduction or congruence transformation I can determine the scale factor for a given.

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Presentation on theme: "LESSON 7-1 I can determine whether a dilation is an enlargement, a reduction or congruence transformation I can determine the scale factor for a given."— Presentation transcript:

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4 LESSON 7-1 I can determine whether a dilation is an enlargement, a reduction or congruence transformation I can determine the scale factor for a given dilation

5 size

6 image preimage enlargement reduction congruent

7 reduction 3/6 or 0.5 enlargement 6/4 or 1.5

8 22 mm 28 mm 22 mm C’ B’ 66 mm 84 mm 66 mm enlargement 3 A’

9 B’ D’ C’ 1/3 reduction

10 P’(rx, ry)

11 (-4, 4) (-2, -6) (6, 6)

12 (-2, 1.5) (-1, -2) (2.5, -1)

13 r = image preimage 4 = 6 x x = 1.5

14 r = image preimage = x 5 x = 3.33 2 3

15 240 in 96 in 180 in 4 240 = 0.0167 = 1 60 4 240 = x 180 x = 3 in

16 60 in 60 2 = 30 60 2 = x 5 x = 150 in

17 7-1 worksheet ASSIGNMENT

18 LESSON 7-2 I can write ratios. I can use properties of proportions.

19 quotient with the same units a : b Write with : or as a fraction, a/b

20 females : males

21 elective : non-elective 2 :3

22 a : b : c Cannot be written as a fraction Ex: ratio of freshmen to sophomores to juniors

23 5 7 8 x x x 5x + 7x + 8x = 240 20x = 240 x = 12 60 84 96

24 2 10 3 x x x 2x + 10x + 3x = 180 15x = 180 x = 12 24° 120° 36°

25 7x 3x 7x 3x 20x = 140 x = 7 L W L = 49

26 fractionsequal diagonals 4(5) = 10(2)

27 8y =72 y = 9 6x =163.8 x = 27.3

28 4(2x + 3) = 40 8x + 12 = 40 x = 3.5 3(x – 1) = 4(x + 1) 3x – 3 = 4x + 4 x = -7

29 length width 40 9 = 16 x 40x = 144 x = 3.6 3.6 inches

30 miles inches 4 1 = x 3.5 x = 14 14 miles

31 gal miles 5 120 = x 350 x = 14.58333 14.6 gallons

32 wide tall 5 3.5 = x 18 x = 25.7143 25.7 inches 5 3.5 ? 18

33 7-2 worksheet ASSIGNMENT

34 LESSON 7-3 I can identify similar figures. I can find missing side lengths in similar figures.

35 PENTOMINOES

36 USE 4 TILES TO MAKE THIS SHAPE

37 DOUBLING Work with your partner to make a shape like the “F” tile, but twice as big Use colored pencils to record your answer on the back of the worksheet Double as many other Pentominoes as you can. Use the grid paper if needed Record all answers using colored pencils

38 2 2 1 3 4 4 2 6

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43 shape size shape size

44 congruent proportional congruent similar

45 12 8 18 12 15 10 9 6 All = 1.5 Similar,all angles congruent, all sides proportional.

46 X Y Z 3 4 5 10 5 6 3 8 4 All = 2 Similar,all angles congruent, all sides proportional.

47 13 x = 14 7 x = 6.5

48 x 9 = 8 12 x = 6 10 y = 8 12 y = 15

49 Find x first 18 x = 12 18 x = 27 27

50 Find y next! y + 1 24 = 12 18 18(y + 1) = 288 18y + 18 = 288 27 y = 15 x = 27, y = 15

51 11 12 Perimeter = 10 + 11 + 12 = 33

52 J K L MN L 5 12.5 10 y 2 x x = 5 2 x = 4 12.5 y = 5 2 y = 5

53 x + 4 2 = 3x + 3 3 2(3x + 3) =3(x + 4) 6x + 6 = 3x + 12 x = 2

54 7-3 worksheet ASSIGNMENT

55 LESSON 7-4 I can identify similar triangles. I can use similar triangles to solve problems.

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57 SSSSAS ASA AAS HL

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60 similar by SSS~ 32 20 40 25 24 15 == Not similar 36 24 20 18 ≠

61 Not similar 18 16 14 12.5 11 ≠≠ Similar by AA~ 30° 60° ΔMKS ~ΔQTR

62 7-4 worksheet ASSIGNMENT

63 LESSON 7-5 I can use the Triangle Proportionality Theorem to find parts of triangles I can use the Triangle Midsegment Theorem to find parts of triangles. I can recognize and use proportions to find relationships between altitudes, angle bisectors and medians of similar triangles.

64 parallel proportional

65 7 21 6 x 7 6 x = x = 18

66 12 x 6 7 = x = 14 x 14 NQ = 26

67 22 x x + 12 11 22 =x = 12

68 x – 4 x – 6 14 6 = x = 7.5

69 endpoints midpoints2 sides parallel half

70 35 2 = 17.5 X =

71 R S T X Y 12 RS = 2(12) = 24

72 proportional

73 6 5 7 x 5 7 6 x = x = 8.4

74 14 10.5 24 x = 14 10.5 x x = 18

75 x + 2 10 2x + 1 14 = x = 3

76 x 8 x + 2 12 = x = 4

77 7-5 worksheet ASSIGNMENT

78 WARM-UP… PLEASE SHOW WORK! Suppose the triangles below are similar. Find x, y and z x y z 3 5 4.5 6 14 17.5 x = 4y = 7.5 z = 10.5

79 LESSON 7-6 I can solve problems involving relationships between parts of a right triangle and the altitude (height) to its hypotenuse (longest side).

80 ΔABC D A C D CB ΔACDΔCBD

81 2 x x 6 2 x x 6 = = 3.46

82 3 x y 9 y x 12 3 x x = 9 y y = = 6= 10.39

83 2 y z 5 z y 7 x x 2 x x 5 = 2 y y 7 = 5 z z 7 = x = 3.16y = 3.74z = 5.92

84 2 x x 6 = 2 y y 4 = 4 z z 6 = x = 3.46y = 2.83z = 4.90

85 7-6 worksheet ASSIGNMENT


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