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Sketching a quadratic graph Sketch the graph of the following quadratic function f(x) or y = -5+x-x 2 Show clearly the coordinates of the points where the curve crosses both the coordinate axes, the line of symmetry and the coordinates of the vertex. Mr Petros Tsichlakis
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Model Answer 1)SHAPE Since a = -1 is negative, our parabola is a ∩ shape. 2) y-crossing Since c = -5, our curve crosses the y axis at y=-5 Alternatively: We set x=0 in the equation y = -5+x-x 2 and this will give us the value of y: f(0) = y = -5+0 – 0 2 = -5 Coordinates of y-crossing (0,-5) Our equation is a quadratic of the form y=ax 2 +bx+c therefore a=-1 b=1 and c=-5 Mr Petros Tsichlakis
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y x 0 --------------------- -------------- Mr Petros Tsichlakis
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