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Problem Solving; Venn Diagrams; Patterns; Pascal’s Triangle; Sequences
MATH st Exam Review Problem Solving; Venn Diagrams; Patterns; Pascal’s Triangle; Sequences
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Problem Solving Polya’s 4 Steps Understand the problem Devise a plan
Carry out the plan Look back
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Problem Solving Strategies for Problem Solving Make a chart or table
Draw a picture or diagram Guess, test, and revise Form an algebraic model Look for a pattern Try a simpler version of the problem Work backward Restate the problem Eliminate impossible situations Use reasoning
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Problem Solving How many hand shakes? Playing darts Tetrominos
Who am I? Triangle puzzle
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Venn Diagrams Vocabulary Intersection Universe Union Element
Set Subset Disjoint Mutually Exclusive Finite Intersection Union Compliment Empty Set Infinite
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Venn Diagrams What can you say about A and B? A Ç B = Æ A È B = {A, B}
A and B are mutually exclusive or disjoint A B
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Venn Diagrams What can you say about A and B? A Ç B = A È B = A’ Ç B =
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Venn Diagrams What can you say about A, B, and C?
A Ç B C =? A È B C =? (A Ç C) B =? A Ç (C B) =? (A Ç B) C =? C Ç (A B) =? (B Ç C) A =? B Ç (C A) =? (A’ Ç B) C =? (A’ È B) C =? A’ Ç B’ C’ =? A’ B’ C’ =? Etc. B A C
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Patterns Triangular Numbers Etc. T T T3 T4 Tn = Tn-1 + n
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Patterns Square Numbers Etc. S1 S2 S S4 Sn = n2
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Patterns Rectangular Numbers R1 R2 R3 R4 Etc. Rn = n (n + 1)
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Pascal’s Triangle Expanding a binomial expression: (a + b)0 = 1
(a + b)1 = a + b (a + b)2 = a2 + 2ab + b2 (a + b)3 = a3 + 3a2b + 3ab2 + b3 (a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4
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Pascal’s Triangle Vocabulary Expansion – the sum of all of the terms
Coefficient – the number in front of the variable(s) for a particular term Variable(s) – the letters AND their exponents for a particular term Term – the coefficient AND the variable(s)
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Pascal’s Triangle 1 1 1 1 2 1
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Pascal’s Triangle Magic 11’s 110 1 111 1 1 112 1 2 1 113 1 3 3 1
Fails to work after this…
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Arithmetic Sequences The difference between any two consecutive terms is always the same. Examples: 1, 2, 3, … 1, 3, 5, 7, … 5, 10, 15, 20, … Non-Examples 1, 4, 9, 16, … 2, 6, 12, 20, …
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Arithmetic Sequences The nth number in a series: Example
an = a1 + (n – 1) d Example Given 2, 5, 8, …; find the 100th term n = 100; a1 = 2; d = 3 a100 = 2 + (100 – 1) 3 a100 = 2 + (99) 3 a100 = a100 = 299
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Arithmetic Sequences Summing or adding up n terms in a sequence:
Example: Given 2, 5, 8, …; add the first 50 terms n = 50; a1 = 2; a50 = 2 + (50 – 1) 3 = 149 S50 = (50/2) ( ) S50 = 25 (151) S50 = 3775
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Arithmetic Sequences Summing or adding up n terms in a sequence:
Example: Given 2, 5, 8, …; add the first 51 terms n = 51; a1 = 2; a2 = 5; a51 = 2 + (51 – 1) 3 = 152 S51 = 2 + ((51-1)/2) ( ) S51 = 2 + (50/2) ( ) S51 = (157) S51 = S51 = 3927
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Geometric Sequences The ratio between any two consecutive terms is always the same. Examples: 1, 2, 4, 8, … 1, 3, 9, 27, … 5, 20, 80, 320, … Non-Examples 1, 4, 9, 16, … 2, 6, 12, 20, …
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Geometric Sequences The nth number in a series: Example an = a1 r(n-1)
Given 5, 20, 80, 320, …; find the 10th term n = 10; a1 = 5; r = 20/5 = 4 a10 = 5 (4(10-1)) a10 = 5 (49) a10 = 5 (262144) a10 =
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Geometric Sequences Summing or adding up n terms in a sequence:
Example: Given 5, 20, 80, 320, …; add the first 7 terms n = 7; a1 = 5; r= 20/5 = 4 S7 = 5(1 – 47)/(1 – 4) S7 = 5(1 – 16384)/(– 3) = 5(– 16383)/(– 3) S7 = (– 81915)/(– 3) = (81915)/(3) S7 = 27305
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Fibonacci Sequences 1, 1, 2, 3, … Seen in nature Golden ratio
Pine cone Sunflower Snails Star fish Golden ratio (n + 1) term / n term of Fibonacci Golden ratio ≈ 1.618
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Test Taking Tips Get a good nights rest before the exam
Prepare materials for exam in advance (scratch paper, pencil, and calculator) Read questions carefully and ask if you have a question DURING the exam Remember: If you are prepared, you need not fear
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