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Published bySuzanna Natalie Blankenship Modified over 9 years ago
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Algebra 1 Ch.10 Notes Page 81 P Factoring to Solve Quadratic Equations
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Zero Product Property If ab = 0, then a = 0 or b = 0
What can x = to give you a zero in part of the problem??? (x + 5)(2x - 6) = 0 (x + 7)(x - 4) = 0 (3x - 6)(4x + 2) = 0
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x2 - 8x - 48 = 0 x2 + 6x + 8 = 0 Solving by Factoring
1. Factor (Mult. to ac and Add to b) 2. Use Zero product property to find zeros x2 + 6x + 8 = 0 x2 - 8x - 48 = 0
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2x2 - 5x = 88 x2 - 12x = -36 Solving by Factoring
1. Factor (Mult. to ac and Add to b) 2. Use Zero product property to find zeros 2x2 - 5x = 88 x2 - 12x = -36
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y = x2 + x - 2 y = -x + 1 Substitution Activity
Use Substitution and Factoring to solve this system of equations... Where do the equations Cross? (Without Graphing) y = x2 + x - 2 y = -x + 1
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