1. Matched Pairs t-procedures: Subjects are matched according to characteristics that affect the response, and then one member is randomly assigned to treatment 1 and the other to treatment 2. Recall that twin studies provide a natural pairing. Before and after studies are examples of matched pairs designs, but they require careful interpretation because random assignment is not used. Apply the one-sample t procedures to the differences

2. Confidence Intervals for Matched Pairs

3. Example #1 Archaeologists use the chemical composition of clay found in pottery artifacts to determine whether different sites were populated by the same ancient people. They collected five random samples from each of two sites in Great Britain and measured the percentage of aluminum oxide in each. Based on these data, do you think the same people used these two kiln sites? Use a 95% confidence interval for the difference in aluminum oxide content of pottery made at the sites and assume the population distribution is approximately normal. Can you say there is no difference between the sites? New Forrest 20.818 15.818.3 Ashley Trails 19.114.816.718.317.7 Difference 1.73.21.3-2.5.6

4. P:μ n = New Forrest percentage of aluminum oxide The true mean difference in aluminum oxide levels between the New Forrest and Ashley Trails. μ a = Ashley Trails percentage of aluminum oxide μ d = μ n - μ a = Difference in aluminum oxide levels

5. A: SRS: Normality: Independence: N:Matched Pairs t-interval Says randomly selected Says population is approx normal It is safe to assume that there are more than 50 samples available

6. I: df = 5 – 1 =4

7. I: df = 20 – 1 = 19

8. C:I am 95% confident the true mean difference in aluminum oxide levels between the New Forrest and Ashley Trails is between –1.754 and 3.4743. Can you say there is no difference between the sites? Yes, zero is in the confidence interval, so it is safe to say there is no difference.

9. Example #2 The National Endowment for the Humanities sponsors summer institutes to improve the skills of high school language teachers. One institute hosted 20 Spanish teachers for four weeks. At the beginning of the period, the teachers took the Modern Language Association’s listening test of understanding of spoken Spanish. After four weeks of immersion in Spanish in and out of class, they took the listening test again. (The actual spoken Spanish in the two tests was different, so that simply taking the first test should not improve the score on the second test.) Below is the pretest and posttest scores. Give a 90% confidence interval for the mean increase in listening score due to attending the summer institute. Can you say the program was successful?

10. SubjectPretestPosttestSubjectPretestPosttest 13029113032 22830122928 33132133134 42630142932 52016153432 63025162027 73431172628 81518 2529 92833193132 102025202932

11. P:μ B = Pretest score The true mean difference in test scores between the Pretest and Posttest μ d = μ B - μ A = Difference in test scores μ A = Posttest score

12. A: SRS: Normality: When you are given the data you can graph it – use Normal Probability Plot We must assume the 20 teachers are randomly selected

14. A: SRS: Normality: Independence: N:Matched Pairs t-interval We must assume the 20 teachers are randomly selected 15<n<30 and distribution is approximately normal, so safe to assume It is safe to assume that there are more than 200 Spanish teachers

15. I: df = 20 – 1 = 19

16. I: df = 20 – 1 = 19

17. C:I am 90% confident the true mean difference in test scores between the Pretest and Posttest is between –2.689 and –0.2115. Can you say the program was successful? Yes, zero is not in the confidence interval, so the pretest score is lower than the posttest score.