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Lecture 13—Circuits part 2 Monday, February 16
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Series Resistors Slide 23-17 In series, current the same in both resistors.
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Parallel Resistors Slide 23-18 In parallel, voltage is the same.
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What is the equivalent resistance of the following circuit? Find the current in and the potential difference across each element in the following circuit. Slide 23-21
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What is the potential difference across the 200 resistor? 1.2 v 2.3 v 3.4.5 v 4.7.5 v 5.Not enough info
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Find equivalent resistor Start at right side: – Series eq = 15Ω – Two 15Ω in parallel Par eq = 7.5 Ω 10Ω 15
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Continue, diagram is now Now in series equivalent = 10Ω Now in parallel equivalent = 5Ω 10 7.5 2.5 5.0 10 5.0
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Continue Finally in series: – R eq =10 Ω 5 5.0
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Now find all currents and voltages Find current in equivalent resistor 10v 10
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Homework due Friday 22: CQ9, CQ11, CQ12, CQ15, 28, 31, 32, 35, 49, 61, 62, WB 22: 8-14 CQ9 simple loop CQ11 R=ρL/A 35 WB22-10
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Homework due Today 23: 4-5 Measuring current and voltage, complex circuits—how to simplify 23: CQ1, CQ2, CQ3, 1, 4, 5, 6, 7, 10, 11, 15, 47, 52, WB 23: 1-6 CQ2 1, 5, 7, 47 WB23: 3,5
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