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Atomic Structure. Wave-Particle Duality All waves have a characteristic wavelength,, and amplitude, A. Frequency,, of a wave is the number of cycles.

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Presentation on theme: "Atomic Structure. Wave-Particle Duality All waves have a characteristic wavelength,, and amplitude, A. Frequency,, of a wave is the number of cycles."— Presentation transcript:

1 Atomic Structure

2 Wave-Particle Duality

3 All waves have a characteristic wavelength,, and amplitude, A. Frequency,, of a wave is the number of cycles which pass a point in one second. Speed of a wave, c, is given by its frequency multiplied by its wavelength: For light, speed = c = 3.00x10 8 m s -1. The speed of light is constant! The speed of light is constant Higher Quality video (2:30 into video). The Wave Nature of Light

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7 X – raysMicrowavesComment(s) Wavelength: λ (m)1.00x10 -10 m1.00x10 -2 m Frequency: ν (s -1 ) Energy: E (J)

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9 Planck: energy can only be absorbed or released from atoms in certain amounts called quanta. The relationship between energy and frequency is where h is Planck’s constant ( 6.626  10 -34 J s ). Quantized Energy and Photons

10 The Photoelectric Effect and Photons Einstein assumed that light traveled in energy packets called photons. The energy of one photon is: Quantized Energy and Photons

11 Nature of Waves: Quantized Energy and Photons X – raysMicrowavesComment(s) Wavelength: λ (m)1.00x10 -10 m1.00x10 -2 m Frequency: ν (s -1 )3.00x10 -18 s -1 3.00x10 -10 s -1 Energy: E (J)

12 Line Spectra Radiation composed of only one wavelength is called monochromatic. Radiation that spans a whole array of different wavelengths is called continuous. White light can be separated into a continuous spectrum of colors. Note that there are no dark spots on the continuous spectrum that would correspond to different lines. Line Spectra and the Bohr Model

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14 Bohr Model Colors from excited gases arise because electrons move between energy states in the atom. (Electronic Transition) Line Spectra and the Bohr Model Bohr Video

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16 Fall 12

17 Bohr Model Since the energy states are quantized, the light emitted from excited atoms must be quantized and appear as line spectra. After lots of math, Bohr showed that where n is the principal quantum number (i.e., n = 1, 2, 3, … and nothing else). Line Spectra and the Bohr Model

18 Bohr Model We can show that When n i > n f, energy is emitted. When n f > n i, energy is absorbed Line Spectra and the Bohr Model

19 Bohr Model Line Spectra and the Bohr Model CyberChem (Fireworks) video Mathcad (Balmer Series)

20 Line Spectra and the Bohr Model: Balmer Series Calculations

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23 Fall 2012

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25 Line Spectra and the Bohr Model: Balmer Series Calculations

26 Limitations of the Bohr Model Can only explain the line spectrum of hydrogen adequately. Can only work for (at least) one electron atoms. Cannot explain multi-lines with each color. Electrons are not completely described as small particles. Electrons can have both wave and particle properties. Line Spectra and the Bohr Model

27 Knowing that light has a particle nature, it seems reasonable to ask if matter has a wave nature. Using Einstein’s and Planck’s equations, de Broglie showed: The momentum, mv, is a particle property, whereas is a wave property. de Broglie summarized the concepts of waves and particles, with noticeable effects if the objects are small. The Wave Behavior of Matter

28 The Uncertainty Principle Heisenberg’s Uncertainty Principle: on the mass scale of atomic particles, we cannot determine exactly the position, direction of motion, and speed simultaneously. For electrons: we cannot determine their momentum and position simultaneously. If  x is the uncertainty in position and  mv is the uncertainty in momentum, then The Wave Behavior of Matter

29 Energy and Matter Size of MatterParticle PropertyWave Property Large – macroscopic MainlyUnobservable Intermediate – electron Some Small – photonFewMainly E = m c 2

30 Schrödinger proposed an equation that contains both wave and particle terms. Solving the equation leads to wave functions. The wave function gives the shape of the electronic orbital. [“Shape” really refers to density of electronic charges.] The square of the wave function, gives the probability of finding the electron ( electron density ). Quantum Mechanics and Atomic Orbitals TBBT: QM-joke

31 Quantum Mechanics and Atomic Orbitals Solving Schrodinger’s Equation gives rise to ‘Orbitals.’ These orbitals provide the electron density distributed about the nucleus. Orbitals are described by quantum numbers. Sledge-O-Matic- Analogy

32 Orbitals and Quantum Numbers Schrödinger’s equation requires 3 quantum numbers: 1.Principal Quantum Number, n. This is the same as Bohr’s n. As n becomes larger, the atom becomes larger and the electron is further from the nucleus. ( n = 1, 2, 3, 4, …. ) 2.Angular Momentum Quantum Number, . This quantum number depends on the value of n. The values of  begin at 0 and increase to (n - 1). We usually use letters for  (s, p, d and f for  = 0, 1, 2, and 3). Usually we refer to the s, p, d and f-orbitals. 3.Magnetic Quantum Number, m . This quantum number depends on . The magnetic quantum number has integral values between -  and + . Magnetic quantum numbers give the 3D orientation of each orbital. Quantum Mechanics and Atomic Orbitals

33 Quantum Numbers of Wavefuntions Quantum #SymbolValuesDescription Principal n1,2,3,4,…Size & Energy of orbital Angular Momentum  0,1,2,…(n-1) for each n Shape of orbital Magneticmm -  …,0,…+  for each  Relative orientation of orbitals within same  Spinmsms +1/2 or –1/2Spin up or Spin down Angular Momentum Quantum # (  ) Name of Orbital 0 s (sharp) 1 p (principal) 2 d (diffuse) 3 f (fundamental) 4 g

34 Quantum Mechanics and Atomic Orbitals nℓ Orbital Name m ℓ (“sub-orbitals) Comment

35 Orbitals and Quantum Numbers Quantum Mechanics and Atomic Orbitals

36 The s-Orbitals Representations of Orbitals

37 The p-Orbitals Representations of Orbitals

38 d-orbitals

39 Many-Electron Atoms Orbitals and Their Energies Orbitals CD

40 Electron Spin and the Pauli Exclusion Principle Many-Electron Atoms

41 Electron Spin and the Pauli Exclusion Principle Since electron spin is quantized, we define m s = spin quantum number =  ½. :Pauli’s Exclusions Principle: no two electrons can have the same set of 4 quantum numbers. Therefore, two electrons in the same orbital must have opposite spins. Many-Electron Atoms

42 Figure 6.27 Orbitals CD

43 Figure 6.28 Orbitals CD

44 Many-Electron Atoms Orbitals and Their Energies Orbitals CD

45 Electron Configurations – I SpeciesElectron ConfigurationBox OrbitalComment

46 Electron Configurations - II SpeciesElectron ConfigurationBox OrbitalComment

47 Metals, Nonmetals, and Metalloids Metals Figure 7.14

48 Two Major Factors: principal quantum number, n, and the effective nuclear charge, Z eff. Periodic Trends

49 Figure 7.5: Radius video Clip

50 Figure 7.6

51 Figure 7.10 IE clip

52 Figure 7.9

53 Electron Affinities Electron affinity is the opposite of ionization energy. Electron affinity: the energy change when a gaseous atom gains an electron to form a gaseous ion: Cl(g) + e -  Cl - (g) Electron affinity can either be exothermic (as the above example) or endothermic: Ar(g) + e -  Ar - (g)

54 Figure 7.11: Electron Affinities

55 Group Trends for the Active Metals Group 1A: The Alkali Metals

56 Group Trends for the Active Metals Group 2A: The Alkaline Earth Metals

57 Group Trends for Selected Nonmetals Group 6A: The Oxygen Group

58 Group Trends for Selected Nonmetals Group 7A: The Halogens

59 Group Trends for the Active Metals Group 1A: The Alkali Metals Alkali metals are all soft. Chemistry dominated by the loss of their single s electron: M  M + + e - Reactivity increases as we move down the group. Alkali metals react with water to form MOH and hydrogen gas: 2M(s) + 2H 2 O(l)  2MOH(aq) + H 2 (g)

60 Group Trends for the Active Metals Group 2A: The Alkaline Earth Metals Alkaline earth metals are harder and more dense than the alkali metals. The chemistry is dominated by the loss of two s electrons: M  M 2+ + 2e -. Mg(s) + Cl 2 (g)  MgCl 2 (s) 2Mg(s) + O 2 (g)  2MgO(s) Be does not react with water. Mg will only react with steam. Ca onwards: Ca(s) + 2H 2 O(l)  Ca(OH) 2 (aq) + H 2 (g)

61 Atomic Structure


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