1. How to Figure a Bill of Materials

2. Materials Being Used ItemQuantityUnit CostTotal Cost ¾” Plywood$35 ½” OSB$25 2x4x8 Studs$3 2x4x16$7 2x12x16$9 Trusses$150 Shingles$ Tile$12 Drywall$ 18 Total

3. 30 45 Spacing = 16”oc

4. Floor 30 45 Materials – 2x12x16’s – ¾” Plywood Equations – Distance x 12/Spacing + 1 – Area/32 – End Caps

5. Floor 30 45 2x12x16’s – Distance x 12/spacing + 1 – 45x12/16+1= – 34.75 = 35 – But a 16’ Board will not reach 30’ – 35 x 2= 70 End Caps – Length x 2/board length – 45x2/16 – 5.63 = 6 Plywood – Area/32 – 45 x 30/32 – 42.2 = 43

6. Walls 30 45 Materials – 2x4x8 Studs – 2x4x16 – ½” OSB Equations – Distance x 12/Spacing + 1 – Area/32 – Sills/Top Plate

7. Wall 30 45 2x4x8 Studs – Distance x 12/spacing +1 – 45x12/16+1 34.75 = 35x 2= 70 – 30x12/16+1 23.5= 24x2= 48 2x4x16 – (Length x 2/ Board length)x3 – (45+30)x2/16 9.4 = 10 x3= 30

8. Wall 30 45 OSB – Area/ 32 – Wall Height – 45x8/32 11.25= 12 x 2 = 24 – 30x8/32 7.5 = 8 x 2 = 16 – Total Sheets 24+16= 40

9. Roof 30 45 Materials – Trusses Equations Distance x 12/Spacing + 1 Trusses – 45x12/16+1 35

10. Roof 36’ Height= 8’ Materials – ½” OSB – Shingles Equations – Pythagorean Theorem – Area/32 – Area/100

11. Roofing OSB – Pythagorean Theorem (8x8)+(18x18)=(CxC) 64+324 388 19.7= 20 – Area/32 20x45/32 28.1= 29 x2=28 36’ Height= 8’

12. Roofing Shingles – 45 x 20/100 – 9 x 2 – 18 Bundles – Shingles are sold in bundles that cover 10’ x 10’ 36’ Height= 8’

13. Drywall 30 45 Materials – 4x12 Drywall Equations – Area/48 Problem – 45x8/48 7.5 = 8 – 30x8/48 5 – 45x30/48 28.2= 29 – 29+5+8=

14. Tile 30 45 Materials – 12” Tile – 10 Tile/Box Equations – Area/ Coverage Area – 45x30/1 – 1350 – 1350/10 – 135 Boxes

15. Materials Being Used ItemQuantityUnit CostTotal Cost ¾” Plywood$35 ½” OSB$25 2x4x8 Studs$3 2x4x16$7 2x12x16$9 Trusses$150 Shingles$ Tile$12 Drywall$ 18 Total