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Published byAbel May Modified over 9 years ago
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Kyla, Maurice, Amari, Deja, Demarcus, Twylah see me
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Do p. 86-88 25, 45, 65, 79
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Objectives: By the end of class, students will be able to: Solve equations with one or more steps. with 90% or above mastery.
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13. – 34 = 6m – 4 +4 +4 Add 4 on both sides -30 = 6m 6 6 Divide 6 on both sides -5 = m
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15. y - 6 = 8 5 + 6 +6 Add 6 on both sides y = 14 5 (5) y = 14 (5) Multiply 5 on both sides 5 y = 70
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19. n – 2 = 2 7 (7) n – 2 = 2 (7) Multiply 7 on both sides 7 n – 2 = 14 +2 + 2 n = 16
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23. Financial Literacy: Important Facts Raul chose the business plan and has budgeted $100 per month. Write an equation for this situation, and determine how many minutes per month he can use the phone and stay within budget. Let m = number of minutes per month.15m + 49.99 = 100.00 - 49.99 - 49.99.15m = 50.01.15.15 m = 333.40 650 + 333 = 983 minutes Raul can use 983 minutes.
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Do p. 93 1 - 5, 7 and 8 On the white boards
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27. Find three consecutive odd integers whose sum is 57. Let n = the smallest consecutive odd integer Let n + 2 = the next largest odd integer Let n + 4 = the largest consecutive odd integer n + (n + 2) + (n + 4) = 57 3n + 6 = 57 - 6 -6 3n = 51 3 3 n = 17 the smallest odd integer So, 17, 19, 21 are three consecutive odd integers whose sum is 57.
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40. Family: The ages of 3 brothers are consecutive integers with the sum of 96. Let n = the smallest consecutive integer Let n + 1 = the next largest consecutive integer Let n + 2 = the largest consecutive integer n + (n + 1) + (n + 2) = 96 3n + 3 = 96 - 3 -3 3n = 93 3 3 n = 31 the youngest age So, 31, 33, and 35 are the brother’s ages.
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Do p. 93 #9, 10 P. 102 Do 48
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1. p. 102 #52 2. p. 102 #53
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