1. © 2010 Pearson Education, Inc. All rights reserved Constructions, Congruence, and Similarity Chapter 12

2. Slide 12.5- 2 Copyright © 2010 Pearson Addison-Wesley. All rights reserved. 12-5 Lines and Linear Equations in a Cartesian Coordinate System  Equations of Vertical and Horizontal Lines  Equations of Lines  Using Similar Triangles to Determine Slope  Systems of Linear Equations  Substitution Method  Elimination Method  Solutions to Various Systems of Linear Equations  Fitting a Line to Data

3. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 3 The Cartesian coordinate system enables us to study both geometry and algebra simultaneously. Cartesian Coordinate System A Cartesian coordinate system is constructed by placing two number lines perpendicular to each other.

4. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 4 Cartesian Coordinate System x-axisy-axis

5. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 5 Cartesian Coordinate System The location of any point P can be described by an ordered pair of numbers (a, b), where a perpendicular from P to the x-axis intersects at a point with coordinate a and a perpendicular from P to the y-axis intersects at a point with coordinate b; the point is identified as P(a, b).

6. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 6 Equations of Vertical and Horizontal Lines Every point on the x-axis has a y-coordinate of zero. Thus, the x-axis can be described as the set of all points (x, y) such that y = 0. The x-axis has equation y = 0. Every point on the y-axis has a x-coordinate of zero. Thus, the y-axis can be described as the set of all points (x, y) such that x = 0 and y is an arbitrary real number. The y-axis has equation x = 0.

7. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 7 Example 12-16 Sketch the graph for each of the following: a.x = 2b.y = 3

8. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 8 Example 12-16 (continued) c.x < 2 and y = 3

9. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 9 Equations of Vertical and Horizontal Lines In general, the graph of the equation x = a, where a is some real number, is the line perpendicular to the x-axis through the point with coordinates (a, 0). Similarly, the graph of the equation y = b is the line perpendicular to the y-axis through the point with coordinates (0, b).

10. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 10 Equations of Lines All points corresponding to arithmetic sequences lie along lines.

11. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 11 A line with a positive slope increases from left to right, a line with negative slope decreases from left to right, and a line with zero slope is horizontal. Slope The slope of the line, usually represented by m, is a measure of steepness. m > 0m = 0m < 0

12. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 12 Example 12-17 Find the equation of the line that contains (0, 0) and (2, 3). The line passes through the origin, so it has the form y = mx. Substitute 2 for x and 3 for y in the equation y = mx and solve for m:

13. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 13 Equations of Lines For a given value of m, the graph of y = mx + b is a straight line through (0, b) and parallel to the line whose equation is y = mx. The graph of the line y = mx + b can be obtained from the graph of y = mx by sliding y = mx up (or down) b units depending on the value of b.

14. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 14 Equations of Lines Any two parallel lines have the same slope or are vertical lines with no slope.

15. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 15 Equations of Lines The graph of y = mx + b crosses the y-axis at point P(0, b). The value of y at the point of intersection of any line with the y-axis is the y-intercept. The slope-intercept form of a linear equation is y = mx + b. The value of x at the point of intersection of any line with the x-axis is the x-intercept.

16. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 16 Example 12-18 Given the equation y − 3x = − 6. Find the slope, the y-intercept, and the x-intercept, then graph the line. The slope is 3 and the y-intercept is − 6. Substitute 0 for y in the equation y = 3x − 6 to find the x-intercept. The x-intercept is 2.

17. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 17 Example 12-18 (continued) (0, − 6) and (2, 0) lie on the line, so plot these points and draw the line through them.

18. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 18 Linear Equations Every line has an equation of the form either y = mx + b or x = a, where m is the slope and b is the y-intercept. Any equation that can be put in one of these forms is a linear equation.

19. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 19 Slope is a measure of the steepness of a line, or the rate of change in the y-values in relation to the corresponding x-values. Both lines k and ℓ have positive slope, but the slope of line k is greater than the slope of line ℓ because line k rises higher than line ℓ for the same horizontal run. Using Similar Triangles to Determine Slope

20. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 20 Determining Slope

21. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 21 Determining Slope

22. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 22 Determining Slope Given two points with the slope m of the line AB is

23. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 23 Example 12-19 a.Given A(3, 1) and B(5, 4), find the slope of AB. b.Find the slope of the line passing through A(−3, 4) and B(−1, 0).

24. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 24 Example 12-20 The points ( − 4, 0) and (1, 4) are on line ℓ. Find the slope of the line and the equation of the line.

25. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 25 Systems of Linear Equations The mathematical descriptions of many problems involve more than one equation, each having more than one unknown. To solve such problems, we must find a common solution to the equations, if it exists.

26. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 26 Example 12-21 May Chin ordered lunch for herself and several friends by phone without checking prices. She paid $18.00 for three soyburgers and twelve orders of fries. Another time she paid $12 for four soyburgers and four orders of fries. Set up a system of equations with two unknowns representing the prices of a soyburger and an order of fries, respectively.

27. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 27 Example 12-21 (continued) Let x be the price in dollars of a soyburger and y be the price of an order of fries. Three soyburgers cost 3x dollars, and twelve orders of fries cost 12y dollars. Because May paid $18.00 for one order, we have 3x + 12y = 18 or x + 4y = 6. Because May paid $12.00 for the other order, we have 4x + 4y = 12 or x + y = 3.

28. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 28 Example 12-21 (continued) If we graph these two lines, the point of intersection is the solution of the system. The lines intersect at (2, 1), so a soyburger costs $2 and fries cost $1.

29. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 29 1.Solve one of the equations for one of the variables. 2.Substitute this for the same variable in the other equation. 3.Solve the resulting equation. 4.Substitute the result back into step 1 to find the other variable. 5.Check solution(s), if required. 6.Write the solution. Substitution Method

30. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 30 Example 12-22 Solve the system Rewrite each equation, expressing y in terms of x.

31. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 31 Example 12-22 (continued) Equate the expressions for y and solve the resulting equation for x.

32. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 32 Example 12-22 (continued) Now substitute and solve for y.

33. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 33 1.Write both equations in standard form, Ax + By = C. 2.Multiply both sides of each equation by a suitable real number so that one of the variables will be eliminated by addition of the equations. (This step may not be necessary.) 3.Add the equations and solve the resulting equation. Elimination Method

34. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 34 4.Substitute the value found in step 3 into one of the original equations, and solve this equation. 5.Check the solution(s), if required. 6.Write the solution. Elimination Method

35. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 35 Elimination Method Solve the system Multiply both sides of the first equation by 2.

36. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 36 Elimination Method Add the equations, then solve for x.

37. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 37 Elimination Method Now substitute for x in either of the original equations, then solve for y.

38. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 38 Geometrically, a system of two linear equations can be characterized as follows: 1.The system has a unique solution if, and only if, the graphs of the equations intersect in a single point. 2.The system has no solution if, and only if, the equations represent parallel lines. 3.The system has infinitely many solutions if, and only if, the equations represent the same line. Solutions to Systems of Linear Equations

39. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 39 Example 12-23 Identify the system as having a unique solution, no solution, or infinitely many solutions. The slopes of the two lines are different, so the lines are not parallel and, therefore, intersect in a single point. Write each equation in slope- intercept form: There is a unique solution.

40. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 40 Example 12-23 (continued) Write each equation in slope- intercept form: The two lines are identical. The system has infinitely many solutions.

41. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 41 Example 12-23 (continued) Write each equation in slope- intercept form: The lines have the same slope, but different y-intercepts, so they are parallel. The system has no solution.

42. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 42 There is often a relationship between two variables. When the data are graphed, there may not be a single line that goes through all of the points, but the points may appear to approximate, or “follow,” a straight line. In such cases, it is useful to find the equation of what seems to be the trend line. Fitting a Line to Data Knowing the equation of such a line enables us to predict an outcome without actually performing the experiment.

43. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 43 The following is a graphical approach to find the trend line. 1.Choose a line that seems to follow the given points so that there are about an equal number of points below the line as above the line. 2.Determine two convenient points on the line and approximate the x- and y-coordinates of these points. 3.Use the points in (2) to determine the equation of the line. Fitting a Line to Data

44. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 44 A shirt manufacturer noticed that the number of units sold depends on the price charged. Example 12-24 Find the equation of a line that seems to fit the data best. Then use the equation to predict the number of units that will be sold if the price per unit is $60.

45. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 45 Select two convenient points. Techniques discussed earlier are used to determine the equation of the line which is then sketched. Example 12-24 (continued)

46. Copyright © 2010 Pearson Education, Inc. All rights reserved. Slide 12.5- 46 Example 12-24 (continued) Substitute x = 60 into the equation to obtain y = − 10(60) + 700 or y = 100. Thus, we predict that 100,000 units will be sold if the price per unit is $60.