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Day 4: Electric Field Calculations for Continuous Charge Distributions A Uniform Distribution of Surface charge A Ring of Continuous Charge A Long Line.

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Presentation on theme: "Day 4: Electric Field Calculations for Continuous Charge Distributions A Uniform Distribution of Surface charge A Ring of Continuous Charge A Long Line."— Presentation transcript:

1 Day 4: Electric Field Calculations for Continuous Charge Distributions A Uniform Distribution of Surface charge A Ring of Continuous Charge A Long Line of Charge A Uniformly Charged Disk Two Parallel Plates

2 A continuous distribution of charge may be treated as a succession of infinitesimal (point) charges, ΔQ, each generating an electric field, ΔE. In the where: is the contribution of the Electric Field due to dQ at a radial distance of “r” away Integrating both sides: or Note: Remember that the electric field is a vector; you will need a separate integral for each component.

3 A Ring of Charge A thin, ring-shaped object of radius a holds a total charge +Q distributed uniformly around it. Let λ be the charge per unit length (C/m). The electric field at a point P on its axis, at a distance x from the center is given by:

4 A Continuous Line of Charge a very long line (ie: a wire) of uniformly distributed charge. Assume x is much smaller than the length of the wire, and let λ be the charge per unit length (C/m). The magnitude of the Electric Field at any point P a distance x away is:

5 The Electric Field or a Uniformly Charged Disk Charge is distributed uniformly over a thin circular disk of radius R. The charge per unit area (C/m 2 ) is σ. The electric field at a point P on the axis of the disk, a distance z above its center is: if z << R

6 Electric Field Between Two Parallel Plates The electric field between two large parallel plates or, which are very thin and are separated by a distance d. One plate carries a uniform surface charge density σ and the other carries a uniform surface charge density –σ, where σ = Q/A (Coulomb / m 2 ) The electric field is uniform if we assume the plates are large compared to the separation distance


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