1. Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy

2. Section 2.4

6. StatementsReasons 1. <BAE is a rt < 1. 2. 3. <DEA is a rt < 3. 4. 5. <CAE <CEA 5. 6. <BAC <DEC 6.

7. StatementsReasons 1. <BAE is a rt < 1. Given 2. Line FK is perpendicular to line KJ 2. If 2 lines form a rt <, then they’re perpendicular. 3. <DEA is a rt < 3. Given 4. Line JH is perpendicular to line KJ 4. Same as 2 5. <CAE <CEA 5. Given 6. <BAC <DEC 6. Compl of <‘s are

8. Given: <A is compl to <C <DBC is compl to <C Conclusion: __?_

9. Given: <A is compl to <C <DBC is compl to <C Conclusion: __?_

10. StatementsReasons 1. Seg KM is perp to seg MO 1. 2. <KMO is a rt <2. 3. <RMO is compl to <KMR 3. 4. <ROM is compl to <POR 4. 5. <KMR <POR5. 6. <ROM <RMO6. Given: Seg KM is perp to seg MO Seg PO is perp to seg MO <KMR <POR Prove: <ROM <RMO R K P M O

11. StatementsReasons 1. Seg KM is perp to seg MO 1. Given 2. <KMO is a rt <2. If segs are perp, they form rt <‘s. 3. <RMO is compl to <KMR 3. If 2 <‘s form a rt <, they are compl. 4. <ROM is compl to <POR 4. Reasons 1-3 5. <KMR <POR5. Given 6. <ROM <RMO6. Compl’s of <‘s are Given: Seg KM is perp to seg MO Seg PO is perp to seg MO <KMR <POR Prove: <ROM <RMO M O R K P

12. Given: <1 is compl to <4 <2 is compl to <3 Ray RT bisects <SRV Prove: Ray TR bisects <STV R T S V 1 2 3 4

13. *Solution Provided by www.darienps.org StatementsReasons 1. Ray RT bisects <SRV1. Given 2. <3 <42. If a ray bisects an angle, then it divides the angle into 2 halves 3. <1 is compl to <43. Given 4. <2 is compl to <34. Given 5. <1 <25. If 2 <‘s are compl to <‘s, then they are 6. Ray TR bisects <STV6. If a ray divides an, into 2 <‘s, then it bisects the <

14.  Rhoad, Richard, George Milauskas, and Robert Whipple. Geometry For Your Enjoyment and Challenge. MA: McDougal, Littell and Company, 1991.  Honors Geometry, Chapter 2, Packet #1, Sections 2.1-2.4  Messman, Bonita. “2.4 Congruent Supplements and Compliments.” Darien High School. 17 January 2010. Web.