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Thermodynamics 101Thermodynamics 101 First Law of Thermodynamics Energy is conserved in a reaction (it cannot be created or destroyed)---sound familiar??? Math representation: Δ E total = Δ E sys + Δ E surr = 0 Δ = “change in” ΔΕ = positive (+), energy gained by system ΔΕ = negative (-), energy lost by system Total energy = sum of the energy of each part in a chemical reaction
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Mg+ 2HCl MgCl 2 + H 2
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Exothermic Temperature increase (--isolated system) Heat is released to surroundings (--open/closed system) q = - value Chemical Thermal Energy
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Endothermic Temperature decrease (--isolated system) All energy going into reaction, not into surroundings Heat absorbed by system, surroundings have to put energy into reaction q = + value Thermal Chemical Energy
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Heat of ReactionHeat of Reaction Amount of heat exchange happening between the system and its surroundings for a chemical reaction. Temperature remains constant Usually reactions happen at constant volume or constant pressure
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How does work factor into heat of reaction? W = -P Δ V If volume is constant ( Δ V), P Δ V = 0 and no other work sooooo If pressure (P) is constant so volume can change, work is being done soooo
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Work in terms of energy change System DOES work------ POSITIVE work value for system, system is LOSING energy System has work on ON it----NEGATIVE work value for system, system is GAINING energy
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Enthalpy (H)Enthalpy (H) Measures 2 things in a chemical reaction: 1)Energy change 2)Amount of work done to or by chemical reaction 2 types of chemical reactions: 1) Exothermic —heat released to the surroundings, getting rid of heat, - ΔΗ 2) Endothermic —heat absorbed from surroundings, bringing heat in, + ΔΗ ** Enthalpy of reaction —heat from a chemical reaction which is given off or absorbed, units = kJ/mol Enthalpy of reaction Heat from a chemical reaction which is given off or absorbed At constant pressure Units = kJ/mol
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Enthalpy (H) cont.Enthalpy (H) cont. Most chemical reactions happen at constant pressure (atmospheric pressure)—open container Temperature and pressure are constant Only work is through pressure/volume Sum of reaction’s internal energy + pressure/volume of system H = U + PV Δ H = Δ U + P Δ V
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Properties of EnthalpyProperties of Enthalpy Extensive Property Dependent on amount of substance used State Function Only deals with current condition Focus on initial and final states Enthalpy changes are unique Each condition has specific enthalpy value SO enthalpy change ( Δ H) also has specific value
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Example 1Example 1 CH 4 + 2O 2 CO 2 + 2H 2 O Δ H = -890.3 kJ
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Example 2Example 2 2HgO 2Hg + O 2 Δ H = + 181.66 kJ HgO Hg + ½ O 2 Δ H = + 90.83 kJ
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More EnthalpyMore Enthalpy The reverse of a chemical reaction will have an EQUAL but OPPOSITE enthalpy change HgO Hg + ½ O 2 Δ H = + 90.83 kJ Hg + ½ O 2 HgO Δ H = - 90.83 kJ SOOO-----total Δ H = 0
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Example 1:Example 1: Based on the following: 2Ag 2 S + 2H 2 O 4Ag + 2H 2 S + O 2 Δ H = +595.5 kJ Find the Δ H for the reaction below: Ag + ½ H 2 S + ¼ O 2 ½ Ag 2 S + ½ H 2 O Δ H = ?
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Example 2:Example 2: Write a chemical equation for ice melting at 0°C through heat absorption of 334 kJ per gram.
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Stoichiometry ReturnsStoichiometry Returns
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Example 1:Example 1: H 2 + Cl 2 2HCl Δ H = -184.6 kJ
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Example 2:Example 2: Calculate the Δ H for the following reaction when 12.8 grams of hydrogen gas combine with excess chlorine gas to produce hydrochloric acid. H 2 + Cl 2 2HCl Δ H = -184.6 kJ
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Example 3:Example 3: Pentaborane (B 5 H 9 ) burns to produce B 2 O 3 and water vapor. The Δ H for this reaction is -8686.6 kJ/mol at 298°K. What is the Δ H with the consumption of 0.600 mol B 5 H 9 ? 2B 5 H 9 + 12O 2 5B 2 O 3 + 9H 2 O
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Calorimetry Experimentally “measuring” heat transfer for a chemical reaction or chemical compound Calorimeter Instrument used to determine the heat transfer of a chemical reaction Determines how much energy is in food Observing temperature change within water around a reaction container ** assume a closed system, isolated container No matter, no heat/energy lost Constant volume
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Specific Heat CapacitySpecific Heat Capacity Amount of heat required to increase the temperature of 1g of a chemical substance by 1°C Units--- J/g °K Unique to each chemical substance Al (s) = 0.901J/g °K H 2 O (l) = 4.18 J/g °K
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q = sm Δ T
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Example 1Example 1 How much heat is needed to raise the temperature of a 500g iron bar from 25° to 50°C ?
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“Coffee Cup” calorimeter“Coffee Cup” calorimeter Styrofoam cup with known water mass in calorimeter Assume no heat loss on walls Initial water temp and then chemical placed inside Final temperature recorded Any temperature increase has to be from the heat lost by the substance SOOO All the heat lost from the chemical reaction or substance is transferred to H 2 O in calorimeter
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“Coffee Cup” calorimeter (cont.) q chemical = -q water
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Example 2: Using the following data, determine the metal’s specific heat. Metal mass = 25.0g Water mass = 20.0g Temperature of large water sample = 95°C Initial temperature in calorimeter = 24.5°C Final temperature in calorimeter = 47.2°C Specific heat of water = 1.00 cal/g °C OR 4.184 J/g °K (KNOW!!!!)
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Δ q rxn Heat gained/lost in experiment with calorimeter Δ H rxn Heat gained/lost in terms of the balanced chemical equation
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Example 3:Example 3: A 50.0 ml sample of 0.250M HCl and 50.0 ml sample of 0.250M NaOH react in a cofee cup calorimeter. The temperature increases from 19.50°C to 21.21°C. Calculate the Δ H for this reaction.
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Homework pp. 251-252 #25, 27, 33-35
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