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Ionisation of water and pH For any Bronsted conjugate Acid-Base pair pH concept pH = -log[H + ] pX = -logX pH scale [H + ] > 10 -7 M, pH < 7 ACIDIC [H.

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Presentation on theme: "Ionisation of water and pH For any Bronsted conjugate Acid-Base pair pH concept pH = -log[H + ] pX = -logX pH scale [H + ] > 10 -7 M, pH < 7 ACIDIC [H."— Presentation transcript:

1 Ionisation of water and pH For any Bronsted conjugate Acid-Base pair pH concept pH = -log[H + ] pX = -logX pH scale [H + ] > 10 -7 M, pH < 7 ACIDIC [H + ] 7 BASIC [H + ] = 10 -7 M, pH = 7 NEUTRAL K a. K b = K w

2 Buffers Every life form is extremely sensitive to slight pH changes. Human blood for example needs to remain within the range 7.38-7.42. Buffers: buffer the system against extreme changes in pH Buffer solutions normally consist of two solutes: a weak Bronsted acid and its conjugate base CH 3 COOH  H + +CH 3 COO -

3 Buffers In general for: HA  A - + H + Henderson-Hasselbach Equation Buffer capacity Q. If we generate 0.15mol H + in a reaction vessel of 1L (with no accompanying volume change) containing 1mol each of CH 3 COOH and CH 3 COO -, what will the solution pH change be? For the same reaction in water what is the pH change?

4 Acid-Base Reactions Acid/Base reactions are reactions that involve the neutralisation of an acid through the use of a base. HCl + NaOH  NaCl + H 2 O In this reaction, the Na + and the Cl - are called spectator ions because they play no role in the overall outcome of the reaction. The only thing that reacts is the H + (from the HCl) and the OH - (from the NaOH). So the reaction that actually takes place is: H + + OH -  H 2 O If in the end, the OH - was the limiting reagent and there are H + 's still left in the solution then the solution is acidic, but if the H + was the limiting reagent and OH - 's were left in the solution then the solution is basic. Titration Titration is the process of mixing acids and bases to analyse one of the solutions. For example, if you were given an unknown acidic solution and a 1 molar NaOH solution, titration could be used to determine what the concentration of the other solution was.

5 Acid-Base Titrations The goal of titration is to determine the equivalence point. The equivalence point is the point in which all the H + and the OH - ions have been used to produce water. Titration also usually involves an indicator. An indicator is a liquid that turns a specific colour at a specific pH. (Different indicators change colours at different pH's). Indicators are chosen to allow a colour change at the equivalence point. Titration of a strong acid with a strong base 50.00mL of 0.020M HCl with 0.100M NaOH H + + OH -  H 2 OK c =1/K w =10 14 at equivalence pt.: nb mol HCl = nb mol NaOH 0.02mol/L x 50/1000 L=0.1mol/L x V e /1000 L V e = 0.001mol HCl  (0.1mol/L x 1/1000 L) = 10 mL pH determined by dissociation of H 2 0: K w = [H + ][OH - ] = 10 -14 [H + ] =  10 -14 = 10 -7 mol/L => pH = 7.00

6 Acid-Base Titrations Titration of a strong acid with a strong base Initial pH:0.02mol/L strong acid.pH = 1.70 before equivalence pt.: when 3.00mL of NaOH has been added Fraction of H + remaining Dilution factor Initial conc. pH = 1.88 after equivalence pt.:10.1mL NaOH added Initial conc. of base Dilution factor pOH = 3.78 pH = 10.22

7 Titration Curves Titration curve of a strong acid with a strong base

8 Titration of a weak acid with a strong base Take the example of a titration of 50.0mL 0.020M CH 3 COOH (K a = 1.8 x 10 -5 ) with 0.10M NaOH CH 3 COOH + NaOH  CH 3 COONa + H 2 O Initial pH:a weak acid equilibrium problem x = 6 x 10 -4, pH = 3.22 CH 3 COOH  H + +CH 3 COO - 0.02-xxx V e = 10mL (as before) Reaction is the reverse of K b for CH 3 COO - base K = 1/K b = 1/(K w / K a ) = 1.8 x 10 9

9 Titration of a weak acid with a strong base Before eq. pt.:buffer system Imagine we have added 3.00mLs of base CH 3 COOH + NaOH  CH 3 COONa + H 2 O Relative Initial: 13/10 Relative final: 7/103/10 One of the simplest ways to treat these problems is to evaluate the quotient in the log using relative concentration before and after the reaction.

10 Titration of a weak acid with a strong base K b = (K w / K a ) = 5.56 x 10 -10 = x 2 /(F-x) x = 3.05 x 10 -6, pOH = 5.52, pH=8.48 (BASIC) When volume of base added = 1/2V e at equivalence pt.: we have a solution of base in water CH 3 COONa + H 2 O  CH 3 COOH + OH - F-xx x

11 Titration of a weak acid with a strong base after equivalence pt.: pH is determined by excess base added For 10.1mL base added in total pOH = 3.78 pH = 10.22

12 Acid-Base Indicators Usually dyes that are weak acids and display different colours in protonated/deprotonated forms. HIn(aq.)  H + (aq.) +In - (aq.) In general we seek an indicator whose transition range (±1pH unit from the indicator pK a ) overlaps the steepest part of the titration curve as closely as possible

13 Acid-base indicators Indicator pH range pKa Acid Form Base Form methyl violet 0.0- 1.6 0.8 yellow blue thymol blue 1.2- 2.8 1.6 red yellow methyl yellow 2.9- 4.0 3.3 red yellow methyl orange 3.1- 4.4 4.2 red yellow bromocresol green 3.8- 5.4 4.7 yellow blue methyl red 4.2- 6.2 5.0 red yellow bromothymol blue 6.0- 7.6 7.1 yellow blue phenol red 6.4- 8.0 7.4 yellow red thymol blue 8.0- 9.6 8.9 yellow blue phenolphthalein 8.0- 9.8 9.7 colourless red thymolphthalein 9.3-10.5 9.9 colourless blue alizarin yellow R 10.1-12.0 11.0 yellow red indigo carmine 11.4-13.0 12.2 blue yellow


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