1. Today, we will burn a gummy worm containing 2.1 g of sucrose (C 12 H 22 O 11 ). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases 5 640 000 joules of energy. The Great Gummy Worm Sacrifice 1. Write a balanced chemical equation for the reaction: 2. The reaction releases 5 640 000 joules for each mole of sucrose consumed, add 5 640kJ to the product side of your equation. 3. Calculate the mass of oxygen needed to completely react the 2.1 g of sucrose in the gummy worm 4. Now use the same strategy to calculate how much energy is released by the combustion of 2.1 g of sucrose

2. Today, we will burn a gummy worm containing 2.1 g of sucrose (C 12 H 22 O 11 ). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases 5 640 000 joules of energy. The Great Gummy Worm Sacrifice 1. Write a balanced chemical equation for the reaction: C 12 H 22 O 6 + O 2 --> CO 2 + H 2 O 12 11 12 2. The reaction releases 5 640 000 joules for each mole of sucrose consumed, add 5 640kJ to the product side of your equation. +5 640kJ

3. Today, we will burn a gummy worm containing 2.1 g of sucrose (C 12 H 22 O 11 ). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases 5 640 000 joules of energy. The Great Gummy Worm Sacrifice Write a balanced chemical equation for the reaction: C 12 H 22 O 6 + O 2 --> CO 2 + H 2 O 12 11 12 The reaction releases 5 640 000 joules for each mole of sucrose consumed, add 5 640kJ to the product side of your equation. +5 640kJ 3. Calculate the mass of oxygen needed to completely react the 2.1 g of sucrose in the gummy worm 2.1g C 12 H 22 O 11 gC 12 H 22 O 11 mol C 12 H 22 O 11 1 342.30 mol C 12 H 22 O 11 mol O 2 12 1mol O 2 gO 2 32.00 1 2.36gO 2 =

4. Today, we will burn a gummy worm containing 2.1 g of sucrose (C 12 H 22 O 11 ). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases 5 640 000 joules of energy. The Great Gummy Worm Sacrifice Write a balanced chemical equation for the reaction: C 12 H 22 O 6 + O 2 --> CO 2 + H 2 O 12 11 12 The reaction releases 5 640 000 joules for each mole of sucrose consumed, add 5 640kJ to the product side of your equation. +5 640kJ 4. Now use the same strategy to calculate how much energy is released by the combustion of 2.1 g of sucrose 2.1g C 12 H 22 O 11 gC 12 H 22 O 11 mol C 12 H 22 O 11 1 342.30 mol C 12 H 22 O 11 kJ5640 1 35kJ or 35 000J = That’s a lot of energy from just 2.1 grams of sucrose! It sounds dangerous. Let’s try it!