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III. Ideal Gas Law and Dalton’s Law of Partial Pressure Gases
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V n A. Avogadro’s Principle b Equal volumes of gases contain equal numbers of moles at constant temp & pressure true for any gas
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PV T VnVn PV nT A. Ideal Gas Law = k UNIVERSAL GAS CONSTANT R=0.0821 L atm/mol K R=8.315 dm 3 kPa/mol K = R 1dm 3 = 1L Merge the Combined Gas Law with Avogadro’s Principle:
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A. Ideal Gas Law UNIVERSAL GAS CONSTANT R=0.0821 L atm/mol K R=8.315 dm 3 kPa/mol K PV=nRT
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GIVEN: P = ? atm n = 0.412 mol T = 16°C = 289 K V = 3.25 L R = 0.0821 L atm/mol K WORK: PV = nRT P(3.25)=(0.412)(0.0821)(289) L mol L atm/mol K K P = 3.01 atm C. Ideal Gas Law Problems b Calculate the pressure in atmospheres of 0.412 mol of He at 16°C & occupying 3.25 L.
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GIVEN: V = ? n = 85 g T = 25°C = 298 K P = 104.5 kPa R = 8.315 dm 3 kPa/mol K C. Ideal Gas Law Problems b Find the volume of 85 g of O 2 at 25°C and 104.5 kPa. = 2.7 mol WORK: 85 g 1 mol = 2.7 mol 32.00 g PV = nRT (104.5)V=(2.7) (8.315) (298) kPa mol dm 3 kPa/mol K K V = 64 dm 3
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Dalton’s Law of Partial Pressure Dalton’s Law of Partial Pressure The total pressure of a mixture of nonreacting gases is equal to the sum of the partial pressures of the individual gases (P total = P 1 + P 2 + P 3 + …)
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Problem 1 b 1 L of N 2 at 50 kPa is mixed with 1 L of O 2 at 60 kPa, to form a 1 L mixture of the gases. What is the resulting pressure? What are the partial pressures? b Total pressure = 60 kPa + 50 kPa = 110 kPa
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Problem 2 b A balloon contains 75 kPa N 2, 15 kPa O 2, 5 kPa CO 2, and water vapour. If atmospheric pressure is 100 kPa what is the partial pressure of water vapour? b 100 - (75 + 15 + 5) = 100 - 95 = 5 kPa
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