1. CS4500CS4500 Dr. ClincyLecture1 Lecture #6 Chapter 5: Addressing (part 1 of 3) Address Structure Classful Addressing Number Systems (Appendix B) Mask – Network Address

2. CS4500CS4500 Dr. ClincyLecture2 IP Addresses Internetworking Protocol (IP) of the Network Layer is responsible for uniquely identifying all devices and connections on the Internet The unique identifier is called an IP address IP address consist of 32 bits (for version 4) Keep in mind that, if a single device had multiple connections to the Internet, you would need an IP address for each connection Address space is 2 32 = 4,294,967,296 32-bit addresses In theoretical terms, 4,294,967,296 connections can be made to the Internet (not really true in real life)

3. CS4500CS4500 Dr. ClincyLecture3 The IP Address has 3 notations: Binary, Dotted-decimal and HexadecimalThe IP Address has 3 notations: Binary, Dotted-decimal and Hexadecimal Binary: 4 Octets:Binary: 4 Octets: 01110101 10010101 00011101 11101010 Dotted-Decimal (or dot notation): IP Addresses For Dotted-Decimal, each number can range from 0 to 255 Hexadecimal: 0111 0101 1001 0101 0001 1101 1110 1010 75 95 1D EA

4. CS4500CS4500 Dr. ClincyLecture4 Change the following IP address from binary notation to dotted-decimal notation: 10000001 00001011 00001011 11101111 Solution 129.11.11.239 EXAMPLES Change the following IP address from dotted-decimal notation to binary notation: 111.56.45.78 Solution 01101111 00111000 00101101 01001110 Find the error, if any, in the following IP address: 111.56.045.78 Solution There are no leading zeroes in dotted-decimal notation (045). Change the following IP addresses from binary notation to hexadecimal notation: 10000001 00001011 00001011 11101111 Solution 810B0BEF 16

5. CS4500CS4500 Dr. ClincyLecture5 IP Addresses: Classful Addressing When IP addressing was first started, it used a concept called “classful addressing”. A newer concept called “classless addressing” is slowly replacing it though. Regarding “classful addressing”, the address space is divided into five classes: A, B, C, D and E. Class# of addressesPercent of the Space A2 31 =214748364850% B2 30 =107374182425% C2 29 =53687091212.5% D2 28 =2684354566.25% E2 28 =2684354566.25%

6. CS4500CS4500 Dr. ClincyLecture6 Finding the class in binary notation Finding the class in decimal notation

7. CS4500CS4500 Dr. ClincyLecture7 Find the class of the address: 00000001 00001011 00001011 11101111 Solution The first bit is 0. This is a class A address. Find the class of the address: 11000001 10000011 00011011 11111111 Solution The first 2 bits are 1; the third bit is 0. This is a class C address. Find the class of the address: 227.12.14.87 Solution The first byte is 227 (between 224 and 239); the class is D. EXAMPLES

8. CS4500CS4500 Dr. ClincyLecture8 Netid and hostid A, B and C class-addresses are divided into network id and host id For Class A, Netid=1 byte, Hostid = 3 bytes For Class B, Netid=2 bytes, Hostid = 2 bytes For Class C, Netid=3 bytes, Hostid = 1 byte

9. CS4500CS4500 Dr. ClincyLecture9 Blocks in class A Class A has 128 blocks or network ids First byte is the same (netid), the remaining 3 bytes can change (hostids) Network id 0 (first), Net id 127 (last) and Net id 10 are reserved – leaving 125 ids to be assigned to organizations/companies Each block contains 16,777,216 addresses – this block should be used by large organizations. How many Host can be addressed ???? The first address in the block is called the “network address” – defines the network of the organization Example Netid 73 is assigned Last address is reserved Recall: routers have addressees

10. CS4500CS4500 Dr. ClincyLecture10 Blocks in class B Class B is divided into 16,384 blocks (65,536 addresses each) 16 blocks are reserved First 2 bytes are the same (netid), the remaining 2 bytes can change (hostids) For example, Network id 128.0 covers addresses 128.0.0.0 to 128.0.255.255 Network id 191.225 is the last netid for this block Example Netid 180.8 is assigned Last address is reserved Recall: routers have addresses

11. CS4500CS4500 Dr. ClincyLecture11 Blocks in class C Class C is divided into 2,097,152 blocks (256 addresses each) 256 blocks are reserved First 3 bytes are the same (netid), the remaining 1 byte can change (hostids) For example, Network id 192.0.0 covers addresses 192.0.0.0 to 192.0.0.255

12. CS4500CS4500 Dr. ClincyLecture12 Class D addresses are used for multicasting; there is only one block in this class. Class E addresses are reserved for special purposes; most of the block is wasted.

13. CS4500CS4500 Dr. ClincyLecture13 Network Addresses The network address is the first address. The network address defines the network to the rest of the Internet. Given the network address, we can find the class of the address, the block, and the range of the addresses in the block Given the network address 17.0.0.0, find the class, the block, and the range of the addresses. Solution The class is A because the first byte is between 0 and 127. The block has a netid of 17. The addresses range from 17.0.0.0 to 17.255.255.255. Given the network address 132.21.0.0, find the class, the block, and the range of the addresses. Solution The class is B because the first byte is between 128 and 191. The block has a netid of 132.21. The addresses range from 132.21.0.0 to 132.21.255.255. Given the network address 220.34.76.0, find the class, the block, and the range of the addresses. The class is C because the first byte is between 192 and 223. The block has a netid of 220.34.76. The addresses range from 220.34.76.0 to 220.34.76.255. Solution

14. CS4500CS4500 Dr. ClincyLecture14 REMINDER: Go Over Converting Binary to Decimal and Vice Versa

15. CS4500CS4500 Dr. ClincyLecture15 Converting Number Systems - Review Base-10 The decimal number system is based on power of the base 10. For example, for the number 1259, the 9 is in the 10^0 column - 1s column the 5 is in the 10^1 column - 10s column the 2 is in the 10^2 column - 100s column the 1 is in the 10^3 column - 1000s column 1259 is 9 X 1 = 9 + 5 X 10 = 50 + 2 X 100 = 200 + 1 X 1000 = 1000 ----- 1259 Base-2 (Binary) The Binary number system uses the same mechanism and concept however, the base is 2 versus 10 The place values for binary are based on powers of the base 2: … 2^7 2^6 2^5 2^4 2^3 2^2 2^1 2^0 128 64 32 16 8 4 2 1

16. CS4500CS4500 Dr. ClincyLecture16 Converting Number Systems - Review So, the binary number 10110011 can be converted to a decimal number 1 X 1 = 1 (right most bit or position) 1 X 2 = 2 0 X 4 = 0 0 X 8 = 0 1 X 16 = 16 1 X 32 = 32 0 X 64 = 0 1 X 128 = 128 (left most bit or position) ------ 179 in decimal To convert from decimal to binary requires a different method called the division/remainder method. The idea is to repeatedly divide the decimal number and resulting quotients by 2. The answer will be the remainders. Example: convert 155 to binary (Start from the top and work down) 155/2 Q = 77, R = 1 (Start) 77/2 Q = 38, R = 1 38/2 Q = 19, R = 0 19/2 Q = 9, R = 1 9/2 Q = 4, R = 1 4/2 Q = 2, R = 0 2/2 Q = 1, R = 0 1/2 Q = 0, R = 1 (Stop) Answer is 10011011. Be careful to place the digits in the correct order.

17. CS4500CS4500 Dr. ClincyLecture17 Converting Number Systems - Review Check the answer (10011011) : 1 X 1 = 1 1 X 2 = 2 0 X 4 = 0 1 X 8 = 8 1 X 16 = 16 0 X 32 = 0 0 X 64 = 0 1 X 128 = 128 ----- 155 Base-16 (Hex) The hexadecimal number system is based 16, and uses the same mechanisms and conversion routines we have already examined. The place values for hexadecimal are based on powers of the base 16 The digits for 10-15 are the letters A - F (A is 10, …….., F is 15) …….. 16^3 16^2 16^1 16^0 4096 256 16 1 The binary number 10110011 can be converted to hexadecimal by grouping bits into groups of 4 bits: 1011 0011 B 3

18. CS4500CS4500 Dr. ClincyLecture18

19. CS4500CS4500 Dr. ClincyLecture19 Binary Arithmetic Refresher Number Converter Tool (your PC calculator) Can go from decimal to binary Can go from binary to decimal

20. CS4500CS4500 Dr. ClincyLecture20Mask A mask is a 32-bit binary number that gives the first address in the block (the network address) when bitwise ANDed with an address in the block. Given the network address, we can easily determine the block and range of addresses Suppose given the IP address, can we determine the network address (beginning of the block) ? To route packets to the correct network, a router must extract the network address from the destination IP address For example, given 134.45.78.2, we know this is a class B, therefore 134.45 is the netid and 134.45.0.0 is the network address (starting address of the block) How would we EXTRACT the network address from the IP address? We would use a MASK.

21. CS4500CS4500 Dr. ClincyLecture21 AND operation If bit is ANDed with 1, it’s preserved If bit is ANDed with 0, it’s changed to a 0. There are 3 default masks: one for each class. The default masks preserve the netid when ANDed with the addresses Class A Default Mask: 255.0.0.0 Class B Default Mask: 255.255.0.0 Class C Default Mask: 255.255.255.0 A simple way to determine the netid for un-subnetted cases: (1) if mask byte is 255, retain corresponding byte of the address, (2) if mask byte is 0, set corresponding address byte to 0.

22. CS4500CS4500 Dr. ClincyLecture22 Examples Given the address 23.56.7.91 and the default class A mask, find the beginning address (network address). Solution The default mask is 255.0.0.0, which means that only the first byte is preserved and the other 3 bytes are set to 0s. The network address is 23.0.0.0. Given the address 132.6.17.85 and the default class B mask, find the beginning address (network address). The default mask is 255.255.0.0, which means that the first 2 bytes are preserved and the other 2 bytes are set to 0s. The network address is 132.6.0.0. Solution Given the address 201.180.56.5 and the class C default mask, find the beginning address (network address). The default mask is 255.255.255.0, which means that the first 3 bytes are preserved and the last byte is set to 0. The network address is 201.180.56.0. Solution

23. CS4500CS4500 Dr. ClincyLecture23 Recall IP Addresses: Classful Addressing Class# of addressesPercent of the Space A2 31 =214748364850% B2 30 =107374182425% C2 29 =53687091212.5% D2 28 =2684354566.25% E2 28 =2684354566.25%

24. CS4500CS4500 Dr. ClincyLecture24 5-bit Address Space Illustration No Netid case 32 addresses/block Number of blocks: 1 Address range per block: 0 to 31 Netids: N/A Network Addresses : 00000 Broadcast Addresses: 11111

25. CS4500CS4500 Dr. ClincyLecture25 1-bit Netid case 16 addresses/block Number of blocks: 2 Address range per block: 0 to 15 Netids: 0, 1 Network Addresses : 00000, 10000 Broadcast Addresses: 01111, 11111 5-bit Address Space Illustration

26. CS4500CS4500 Dr. ClincyLecture26 2-bit Netid Case 8 addresses/block Number of blocks: 4 Address range per block: 0 to 7 Netids: 00, 01, 10, 11 Network Addresses : 00000, 01000, 10000, 11000 Broadcast Addresses: 00111, 01111, 10111, 11111 5-bit Address Space Illustration

27. CS4500CS4500 Dr. ClincyLecture27 3-bit Netid Case 4 addresses/block Number of blocks: 8 Address range per block: 0 to 3 Netids: 000, 001, 010, 011, 100, 101, 110, 111 Network Addresses : 00000, 00100, 01000, 01100 10000, 10100, 11000, 11100 Broadcast Addresses: 00011, 00111, 01011, 01111 10011, 10111, 11011, 11111 5-bit Address Space Illustration

28. CS4500CS4500 Dr. ClincyLecture28 4 addresses/block and 8 addresses/block Number of blocks: 6 Address range per block: 0 to 3 and 0 to 7 Netids: 000, 001, 010, 011, 10, 11 Network Addresses : 00000, 00100, 01000, 01100 10000, 11000 Broadcast Addresses: 00011, 00111, 01011, 01111 10111, 11111 Mixing 3-bit & 2-bit Cases (think of the 32-bit case)