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12.1 & 12.2 – Explore Solids & Surface Area of Prisms and Cones
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Polyhedron: A solid that is bounded by polygons
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Faces: Polygon on the side of the shape Ex: Hex ABCDFE Quad EFKL
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Edges: Where two polygons meet to form a line Ex:
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Vertex: Where 3 polygons meet to form a point Ex:
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Non-Polyhedron: An edge that isn’t a polygon
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Base:Polygon the solid is named after.
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Lateral Faces: Parallelograms or triangles on the sides of the solid
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Prism: Polyhedron with two parallel, congruent bases Named after its base
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Pyramid: Polyhedron with one base and lateral faces Named after its base.
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Regular: All of the faces are congruent regular polygons
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Convex: Any two points on its surface can be connected by a segment that lies entirely inside or on the solid
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Concave: A side of the solid goes inward
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Cross Section: Intersection of a plane and a solid
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Euler’s Theorem: Faces + Vertices = Edges + 2 F + V = E + 2
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Platonic Solids: Regular Polyhedra, only 5. Named after how many faces they have
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Regular Tetrahedron: 4 faces
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Cube: 6 faces
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Regular Octahedron: 8 faces
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Regular Dodecahedron: 12 faces
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Regular Icosahedron: 20 faces
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Determine whether the solid is a polyhedron. If it is, name the polyhedron and state the number of faces, vertices, and edges. Rectangular prism Polyhedron: YES or NO Faces: ___________ Vertices: _________ Edges: ___________ 6 8 12 F + V = E + 2 6 + 8 = 12 + 2 14 = 14
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Determine whether the solid is a polyhedron. If it is, name the polyhedron and state the number of faces, vertices, and edges. curved sides Polyhedron: YES or NO Faces: ___________ Vertices: _________ Edges: ___________
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Determine whether the solid is a polyhedron. If it is, name the polyhedron and state the number of faces, vertices, and edges. Pentagonal Pyramid Polyhedron: YES or NO Faces: ___________ Vertices: _________ Edges: ___________ 6 6 10 F + V = E + 2 6 + 6 = 10 + 2 12 = 12
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Determine whether the solid is a polyhedron. If it is, name the polyhedron and state the number of faces, vertices, and edges. Triangular prism Polyhedron: YES or NO Faces: ___________ Vertices: _________ Edges: ___________ 5 6 9 F + V = E + 2 5 + 6 = 9 + 2 11 = 11
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Determine whether the solid is a polyhedron. If it is, name the polyhedron and state the number of faces, vertices, and edges. curved side Polyhedron: YES or NO Faces: ___________ Vertices: _________ Edges: ___________
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Use Euler’s Theorem to find the value of n. F + V = E + 2 n + 8 = 12 + 2 n + 8 = 14 n = 6
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Use Euler’s Theorem to find the value of n. F + V = E + 2 5 + 6 = n + 2 11 = n + 2 9 = n
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Use Euler’s Theorem to find the value of n. F + V = E + 2 8 + n = 18 + 2 8 + n = 20 n = 12
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Sketch the polyhedron. Cube
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Sketch the polyhedron. Rectangular prism
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Sketch the polyhedron. Pentagonal pyramid
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Determine if the solid is convex or concave. convex
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Determine if the solid is convex or concave. concave
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Determine if the solid is convex or concave. convex
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Describe the cross section formed by the intersection of the plane and the solid. pentagon
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Describe the cross section formed by the intersection of the plane and the solid. circle
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Describe the cross section formed by the intersection of the plane and the solid. triangle
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Cylinder: Prism with circular bases
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Surface area: Area of each face of solid
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Lateral area: Area of each lateral face
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Right Prism: Each lateral edge is perpendicular to both bases
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Oblique Prism: Each lateral edge is NOT perpendicular to both bases
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Net: Two-dimensional representation of a solid
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Surface Area of a Right Prism: SA = 2B + PH B = area of one base P = Perimeter of one base H = Height of the prism H
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Surface Area of a Right Cylinder: H SA = 2B + PH
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1. Name the solid that can be formed by the net. Cylinder
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1. Name the solid that can be formed by the net. Triangular prism
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1. Name the solid that can be formed by the net. rectangular prism Cube?
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2. Find the surface area of the right solid. SA = 2B + PH SA = 2(30) + (22)(7) B = bh B = (5)(6) B = 30 P = 5 + 6 + 5 + 6 P = 22 SA = 60 + 154 SA = 214m2m2
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2. Find the surface area of the right solid. SA = 2B + PH SA = 2(30) + (30)(10) P = 5 + 12 + 13 P = 30 SA = 60 + 300 SA = 360cm 2 c 2 = a 2 + b 2 c 2 = (5) 2 + (12) 2 c 2 = 25 + 144 c 2 = 169 c = 13
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2. Find the surface area of the right solid. cm 2
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2. Find the surface area of the right solid. in 2 144in
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3. Solve for x, given the surface area. SA = 2B + PH 142 = 2(5x) + (2x + 10)(7) B = bh B = 5x P = 5 + x + 5 + x P = 2x + 10 142 = 10x + 14x + 70 142 = 24x + 70 72 = 24x 3ft = x
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3. Solve for x, given the surface area.
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