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Published byLenard Black Modified over 9 years ago
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Simultaneous Equations Diet Balancing
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Simultaneous Equations Used to balance for 2 nutrients Usually protein and energy Balances for required amounts Lb, kg, or Mcal Uses 2 ingredients or 2 mixtures of ingredients
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Simultaneous Equations Identify feeds and their composition Feed A – 10% CP, 80% TDN Feed B – 35% CP, 50% TDN
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Simultaneous Equations Identify animal requirements 0.8 lb CP and 4.0 lb TDN per day Let A = lb of Feed A needed Let B = lb of Feed B needed
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Simultaneous Equations Lb Feed A Lb CP reqmt Equation describing CP Diet must supply 0.8 lb of CP so (A x 0.10) + (B x 0.35) = 0.8 lb CP Lb Feed B CP in Feed ACP in Feed B
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Simultaneous Equations Lb TDN reqmt Equation describing TDN Diet must supply 4.0 lb of TDN so (A x 0.80) + (B x 0.50) = 4.0 lb TDN Lb Feed ALb Feed B TDN in Feed ATDN in Feed B
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Simultaneous Equations 2 equations with the same unknowns 0.10A + 0.35B = 0.8 lb CP 0.80A + 0.50B = 4.0 lb TDN
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Simultaneous Equations Multiply 1 equation by a factor that will make one unknown the same in both 0.10A + 0.35B = 0.8 lb CP 0.80A + 0.50B = 4.0 lb TDN 0.80/0.10 = 8, so multiply 1 st eq by 8
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Simultaneous Equations 8 (0.10A + 0.35B) = 8 (0.8 lb CP) 0.8A + 2.8B = 6.4 lb new equation
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Simultaneous Equations Subtract the 2 nd eq from new equation 0.8A + 2.8B = 6.4 lb new equation 0.8A + 0.5B = 4.0 lb 2 nd equation 0 + 2.3B = 2.4
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Simultaneous Equations Solve for unknown 0 + 2.3B = 2.4 B = 2.4/2.3 B = 1.04 What was B? Lb Feed B
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Simultaneous Equations Substitute 1.04 for B in either original eq 0.10A + 0.35B = 0.8 lb 0.10A + 0.35(1.04) = 0.8 0.10A = 0.8 – 0.364 0.10A = 0.436 A = 0.436/0.10 = 4.36 lb Feed A
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Simultaneous Equations Our diet consists of: 1.04 lb Feed B 4.36 lb Feed A
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Simultaneous Equations Check our work: 1.04 lb Feed B x 0.35 = 0.364 lb CP 4.36 lb Feed A x 0.10 = 0.436 lb CP 0.8 lb CP
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Simultaneous Equations Check our work: 1.04 lb Feed B x 0.50 = 0.52 lb TDN 4.36 lb Feed A x 0.80 = 3.48 lb TDN 4.0 lb TDN
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