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Published byIlene Gregory Modified over 9 years ago
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Bond Enthalpies How does a chemical reaction have energy?
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Bond Energy Energy required to make/break a chemical bond Endothermic reactions Products have more energy than reactants More energy to BREAK bonds Exothermic reactions Reactants have more energy than products More energy to FORM bonds
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Bond Enthalpy Focuses on the energy/heat between products and reactants as it relates to chemical bonding Amount of energy absorbed to break a chemical bond--- amount of energy released to form a bond. Multiple chemical bonds take more energy to break and release more energy at formation Amount of energy absorbed = amount of energy released to break chemical bond to form a chemical bond
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Calculating ΔH rxn. by bond enthalpies (4 th method) Least accurate method ΔH = ΣBE (bonds broken) - ΣBE (bonds formed)
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Example 1: Using average bond enthalpy data, calcaulate ΔH for the following reaction. CH 4 + 2O 2 CO 2 + 2H 2 O ΔH = ? BondAverage Bond Enthalpy C-H413 kJ/mol O=O495 kJ/mol C-O358 kJ/mol C=O799 kJ/mol O-H467 kJ/mol
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Entropy
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Spontaneous vs. Nonspontaneous 1)Spontaneous Process Occurs WITHOUT help outside of the system, natural Many are exothermic—favors energy release to create an energy reduction after a chemical reaction Ex. Rusting iron with O 2 and H 2 O, cold coffee in a mug Some are endothermic Ex. Evaporation of water/boiling, NaCl dissolving in water
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Spontaneous vs. Nonspontaneous 2) Nonspontaneous Process REQUIRES help outside system to perform chemical reaction, gets aid from environment Ex. Water cannot freeze at standard conditions (25°C, 1atm), cannot boil at 25°C **Chemical processes that are spontaneous have a nonspontaneous process in reverse **
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Entropy (S) Measure of a system’s disorder Disorder is more favorable than order ΔS = S (products) - S (reactants) ΔS is (+) with increased disorder State function Only dependent on initial and final states of a reaction Ex. Evaporation, dissolving, dirty house
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Thermodynamic Laws 1 st Law of Thermodynamics Energy cannot be created or destroyed 2 nd Law of Thermodynamics The entropy of the universe is always increasing. Naturally favors a disordered state
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When does a system become MORE disordered from a chemical reaction? (ΔS > 0) 1)Melting 2)Vaporization 3)More particles present in the products than the reactants 4C 3 H 5 N 3 O 9 (l) 6N 2 (g) + 12CO 2 (g) + 10H 2 O (g) + O 2 (g) 4)Solution formation with liquids and solids 5)Addition of heat
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When does a system become LESS disordered from a chemical reaction? (ΔS < 0) 1)Solution formation with liquids and gases
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3 rd Law of Thermodynamics The entropy (ΔS) of a perfect crystal is 0 at a temperature of absolute zero (0°K). No particle motion at all in crystal structure All motion stops
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How do we determine if a chemical reaction is spontaneous? 1)Change in entropy (ΔS) 2)Gibbs Free Energy (ΔG)
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Change in entropy (ΔS) For a chemical reaction to be spontaneous (ΔS T > 0), there MUST be an increase in system’s entropy (Δs sys > 0) and the reaction MUST be exothermic (Δs surr > 0). Exothermic reactions are favored, NOT endothermic reactions. Exothermic (ΔH 0) Endothermic (ΔH > 0, ΔS < 0) ΔS T = Δs sys + Δs surr If ΔS T > 0, then the chemical reaction is spontaneous
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Example 1: Will entropy increase or decrease for the following? a)N 2 (g) + 3H 2 (g) 2NH 3 (g) b)2KClO 3 (s) 2KCl (s) + 3O 2 (g) c)CO (g) + H 2 O (g) CO 2 (g) + H 2 (g) d)C 12 H 22 O 11 (s) C 12 H 22 O 11
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How do we calculate the entropy change (ΔS) in a chemical reaction? Same method as using the enthalpies of formation to calculate ΔH and use the same table. aA + bB cC + dD ΔS° =[c (ΔS° C ) + d(ΔS° D )] - [a (ΔS° A ) + b (ΔS° B )]
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Example 2: Calculate ΔS° for the following reaction at 25°C…. 4HCl (g) + O 2 (g) 2Cl 2 (g) + 2H 2 O (g)
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Homework pp. 382-383 #69, 71-73 pp. 742-743 #19, 27
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