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Published byCleopatra Pauline Baker Modified over 9 years ago
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REDOX electrochemistry
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Spontaneous redox reactions can transfer energy –Electrons (electricity) –Heat Non-spontaneous redox reactions can be made to happen with electricity. Redox reactions involve the transfer of the electron.
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Trends in Oxidation and Reduction Active metals: Lose electrons easily Are easily oxidized Are strong reducing agents Active nonmetals: Gain electrons easily Are easily reduced Are strong oxidizing agents
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Oxidation - is defined as the loss of an electron (LEO - loss of electron; oxidation) -when oxidation happens, charge becomes more positive Fe → Fe 2+ + 2e- 4 Fe (s) + 3 O 2 (aq) → 2 Fe 2 O 3 (s)
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Reduction is defined as the gain of an electron (GER- gain of electrons – reduction - when reduction happens, charge becomes more negative Fe 2+ + 2e- → Fe - term is derived from the observation that metal oxides lose mass when refined to produce the pure metal: 2 Fe 2 O 3 (s) → 4 Fe (s) + 3 O 2 (aq)
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N 2 O → NO Has the nitrogen gained or lost electrons? N 2 O → NO +1 +2 Nitrogen has lost one electron and is therefore being oxidized.
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Each sodium atom loses one electron: Each chlorine atom gains one electron: Lose Electrons = Oxidation Gain Electrons = Reduction
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These pairs of reactions are called half- reactions. For example, in the reaction Cu 2+ (aq) + Fe (s) → Cu (s) + Fe 2+ (aq) two half-reactions occur; iron is oxidized while the copper (II) ion is reduced. Seen another way, the copper (II) ion causes the oxidation of the iron; it is the oxidizing agent. Likewise, the iron is the reducing agent for the copper (II) ion.
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There are five basic rules for the determination of oxidation number: Rule 1:The oxidation number for any atom in its elementary state is 0. Rule 2:The oxidation number for any simple ion is the change on the ion. a.The oxidation number of alkali metals in compounds is 1+ (Li 1+, Na 1+, K 1+, Rb 1+, Cs 1+, Fr 1+ ). b.The oxidation number of alkaline-earth metals in compounds is 2+ (Mg 2+, Ca 2+, and Ba 2+ ).
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Find the oxidation number for magnesium and chlorine
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Rule 3:The oxidation number for oxygen usually is 2-. In peroxides, it is 1-. water peroxide
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Rule 4:The oxidation number for hydrogen is 1+ in all its compounds except in metallic hydrides like NaH or BaH 2, where it is 1-. Rule 5:All other oxidation numbers are assigned so that the sum of oxidation numbers equals the net charge on the molecule or polyatomic ion.
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Find the oxidation numbers H 2 SCa(OH) 2 2(+1) + (-2) = 0 H O (+2) + 2(-2) + 2(+1) = 0 Ca O H
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X + 3(-2) = -1 N O X = +5 X = +6 X + 4(-2) = -2 S O Find the oxidation numbers
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Find the oxidation number of Cr: Ex: Cr 2 O 7 2- 2X + 7(-2) = -2 Cr O X = +6
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Write the oxidation numbers for each atom: S 8 SO 2 S 2 O 3 2- SO 4 2- MgSO 4 H 2 SO 4 0 S = +4 and O = -2 S = +2 and O = -2 S = +6 and O = -2 Mg = +2, S = +6 and O = -2 H = +1, S = +6 and O = -2
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Find the oxidation numbers P 4 P 2 O 5 PCl 5 H 3 PO 4 PO 4 3- Na 3 PO 4 0 P = +5 and O = -2 P = +5 and Cl = -1 H = +1, P = +5 and O = -2 P = +5 and O = -2 Na = +1, P = +5 and O = -2
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A summary of terminology for oxidation- reduction (redox) reactions X Y e-e- transfer or shift of electrons X loses electron(s)Y gains electron(s) X is oxidizedY is reduced X is the reducing agentY is the oxidizing agent X increases its oxidation number Y decreases its oxidation number
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Not all reactions are redox Reactions in which there has been no change in oxidation number are not redox reactions.
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Just like the Bronsted-Lowry theory of acids, oxidation and reduction also happens in pairs; a species cannot donate an electron unless another species gains the electron. Since oxidation and reduction always happen together, these are most often called redox reactions.
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Reducing and oxidizing agents The substance reduced is the oxidizing agent The substance oxidized is the reducing agent Sodium is oxidized – it is the reducing agent Chlorine is reduced – it is the oxidizing agent
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2H 2 ( g ) + O 2 ( g ) → 2H 2 O( g ) 0 0+1-2 The O.N. of H increases; it is oxidized; it is the reducing agent. The O.N. of O decreases; it is reduced; it is the oxidizing agent. FIND THE OXIDATION NUMBERS:
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Find the oxidation numbers: 2Al( s )+ 3H 2 SO 4 ( aq ) Al 2 (SO 4 ) 3 ( aq ) + 3H 2 ( g ) 00+6+1-2+3+6-2 The O.N. of Al increases; it is oxidized; it is the reducing agent. The O.N. of H decreases; it is reduced; it is the oxidizing agent.
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Find the oxidation numbers PbO( s ) + CO( g ) → Pb( s ) + CO 2 ( g ) +2-2+2-2 0+4 The O.N. of C increases; it is oxidized; it is the reducing agent. The O.N. of Pb decreases; it is reduced; it is the oxidizing agent.
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