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Electrical Energy, Electric Fields & DC Circuits

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Presentation on theme: "Electrical Energy, Electric Fields & DC Circuits"— Presentation transcript:

1 Electrical Energy, Electric Fields & DC Circuits
Chapters Electrical Energy, Electric Fields & DC Circuits Herriman High Honors Physics

2 Other Forms of Stored Energy: Chemical Energy
Stored in the Chemical Bonds that make up a substance Often released by combustion (burning) Released as kinetic energy Heat Light Sound *** Demonstration *** Herriman High Honors Physics

3 Electric Charge and Electric Field
Static Electricity – Unmoving charge Two types Positive – lack of electrons Negative – excess electrons Like charges - Repel Opposite Charges - Attract Herriman High Honors Physics

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Electric Charges Charge can be induced by rubbing an object – View demonstrations Charge is detected using an electroscope. Charge can travel via a conductor. Poor conductors are insulators. Herriman High Honors Physics

5 Force Exerted by Charges
Coulomb’s Law F = kQ1Q2/r2 k = 9 x 109 N•m2/C2 Positive solution – repulsion Negative solution - attraction Herriman High Honors Physics

6 (9 x 109 N•m2/C2)(+10 x 10-6 C)(-15 x 10-6 C)/(1.5 m)2
Sample Problem Two charges, Q1 = +10 µC, and Q2 = -15 µC, are separated by 1.5 meters. What is the electrostatic force acting between them? Solution F = kQ1Q2/r2 = (9 x 109 N•m2/C2)(+10 x 10-6 C)(-15 x 10-6 C)/(1.5 m)2 = -0.6 N Practice A P. 566 #1 & 3 Herriman High Honors Physics

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Electric Field Field – Affect that acts at a distance, without contact Examples Electric Field Gravitational Field Electric Field Strength – E = F/q = kQ/r2 Herriman High Honors Physics

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Sample Problem Calculate the strength of an electric field at a point 30 cm from a point charge Q = +3 µC Solution E = kQ/r2 = (9 x 109 N•m2/C2)(+3 x 10-6 C)/(0.3 m)2 = N/C Practice D P. 575 # 1 & 3 Herriman High Honors Physics

9 Chapter 17: Electrical Energy & Current
Electrical Energy is generated from other forms of energy and transmitted over power lines and/or stored in batteries Vocabulary Voltage (V) Force in an electrical system; Volt = Work/Charge = W/q = Joule/Coloumb Current (I) Rate in an electrical system = Charge/time = q/t =Coloumb/sec = 1 Ampere Herriman High Honors Physics

10 Energy in Electrical System
Volts =Work/charge = V =W/q Work is measured in joules (the same as energy) Charge is measured in Coloumbs (C) The charge on an electron is 1.6 x C 1 V = 1 Joule/1 Coloumb Work = Volts * Charge = Vq Herriman High Honors Physics

11 An Old Equation – with a twist
Remember that the equation for the strength of an electric field is given by E = F/Q now we have V = W/Q where W = F x d so V/d = E or V = Ed Herriman High Honors Physics

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Sample Problem How much work is needed to move a 10 μC charge to a point where the potential is 70 V? W = Vq = (70 V)(10 x 10-6 C) = 7 x 10-4 J Practice A P # 1 & 3 Herriman High Honors Physics

13 Electrical Energy Storage
Electrical Energy can be stored in two ways: Batteries Long term storage, even flow of charge Storage ability measured in Volts Capacitors Short term storage, releases charge all at once (boost in charge) Storage capacity measured in Farads (F) 1 Farad = 1 Coloumb/Volt Mathematically Charge = Capacitance * Voltage = q = CV Herriman High Honors Physics

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Sample Problem What charge is stored when a 0.5 F capacitor is attached to a 9 volt source? Solution q = CV = (0.5 F)(9 V) = 4.5 Coloumbs Herriman High Honors Physics

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Capacitance To calculate the capacitance of a plate capacitator C = Kε0A/d where K = the dielectric constant ε0 = the permitivity constant 8.85 x C2/N•m2 A = the area of the plates in m2 d = the distance between the plates in meters Herriman High Honors Physics

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Sample Problem What is the capacitance of a capacitor consisting of 2 plates, each having an area of 0.5 m2, separated by 2 mm of mica? Solution C = Kε0A/d = (7)(8.85 x C2/N•m2)(0.5 m2)/(.002 m) = 1.55 x 10-9 F = 1.55 nF Herriman High Honors Physics

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Energy and Capacitors Energy stored in capacitors is electric potential energy. 𝑃 𝐸 𝑒𝑙𝑒𝑐𝑡𝑟𝑖𝑐 = 1 2 𝑄∆𝑉 Where Q is the charge on one plate and ΔV is the voltage or potential difference Herriman High Honors Physics

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Sample Problem A capacitor connected to a 12 V battery holds 36 µC of charge on each plate. What is the capacitance of the capacitor and how much electrical potential energy is stored in the capacitor? Solution 𝐶= 𝑄 𝑉 = 3.6 𝑥 10 −5 𝐶 12 𝑉 =3 𝑥 1 0 −6 𝐹 𝑃𝐸= 1 2 𝑄𝑉= 1 2 𝐶 𝑉 2 =(0.5)(3 𝑥 1 0 −6 𝐹)(12 𝑉 ) 2 =2.2 𝑥 1 0 −4 𝐽 Practice B P. 607 #2 & 4 Herriman High Honors Physics

19 Electric Current & Resistance
Circuit – A continuous path connected between the terminals of a power source. Current – Flow of Charge I = ΔQ/Δt Current is measured in Coloumbs/Sec which is called an Ampere. Herriman High Honors Physics

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Electric Current Electron Flow is from – terminal to + terminal. Conventional Current is from + terminal to – terminal. Herriman High Honors Physics

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Sample Problem A steady current of 2.5 Amps passes through a wire for 4 minutes. How much charge passed through any point in the circuit? Solution Q = IΔt (2.5 C/s)(240 s) = 600 C Herriman High Honors Physics

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Ohm’s Law Resistance – how much the conductor slows down the flow of electrons through it. Resistance is measured in Ohms (Ω) Ohm’s law -In any Circuit: V = IR or R = V/I Herriman High Honors Physics

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Sample Problem A small flashlight bulb draws a current of 300 mA from a 1.5 V battery. What is the resistance of the bulb? Solution R = V/I = (1.5 V)/(0.3 A) = 5 Ω Herriman High Honors Physics

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Resistor Color Code Resistors are banded in order to describe the amount of resistance they provide. Each resistor is banded with 4 stripes. Band Represents 1 First Digit 2 Second Digit 3 Multiplier 4 Tolerance Herriman High Honors Physics

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Resistor Color Code Bright Black Boys Brown 1 Remember Red 2 Our Orange 3 Young Yellow 4 Girls Green 5 Become Blue 6 Very Violet 7 Good Grey 8 Wives White 9 Gold 5% Silver 10% None 20% Herriman High Honors Physics

26 Red = 2, Green = 5, Blue = 6 and Silver = 10%
Sample Problem Calculate the resistance of a resistor which is banded with the following colors: Red, Green, Blue, Silver. Solution Red = 2, Green = 5, Blue = 6 and Silver = 10% R = ± 10% Or R = 25 MΩ ± 10% Herriman High Honors Physics

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Resistivity Spools or lengths of wire each have their own Resistance. Resistivity of these items can be calculated using the equation: R = ρL/A Where ρ is a constant, L is length, and A is cross sectional area of the wire. Practice D P. 615 #1,3,& 5 Herriman High Honors Physics

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Electric Power Power = Work/time In an Electical System P = QV/t So P = VI = I2R = V2/R Herriman High Honors Physics

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Sample Problem Calculate the resistance of a 40 Watt headlight which is designed to run on 12 Volts. Solution R = V2/P R = (12 V)2/40 Watts = 36 Ω Herriman High Honors Physics

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Sample Problem Calculate the resistance of a spool of copper wire which is 20 m long and has a cross sectional area of 3.4 x 10-6 m2? Solution R = ρL/A= (1.68 x 10-8Ω•m)(20 m)/(3.4 x 10-6 m2) = 1.14 x Ω Herriman High Honors Physics

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Chapter 18: DC Circuits Batteries Connected in Series Increase Voltage Et= E1 + E2 + E3. . . Produce the Same Current It= I1 = I2 = I3. . . Batteries Connected in Parallel Produce the Same Voltage Et= E1 = E2 = E3. . . Increase Current It= I1 + I2 + I3. . . Herriman High Honors Physics

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Sample Problem Calculate the voltage and current when 3 batteries (1.5 V, 0.25 A are connected in A) Series B) Parallel Solution a) Et= E1 + E2 + E3 =1.5 V V V = 4.5 V It= I1 + I2 + I3= 0.25 A b) Et= E1 = E2 = E3=1.5 V It= I1 + I2 + I3=0.25 A A A = 0.75 A Herriman High Honors Physics

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DC Circuits Resistance in Series Rt=R1+R2+R3. . . Resistance in Parallel Herriman High Honors Physics

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Sample Problem Calculate the resistance when a 5 Ω, 6 Ω, and 3 Ω resistor are connected in A) Series B) Parallel Solution a) Rt=R1+R2+R3 = 5 Ω+ 6 Ω+ 3 Ω = 14 Ω b) Rt= 1.43 Ω Herriman High Honors Physics

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In Class Practice Practice A, P ,3, & 5 Practice B, p & 4 Do Practice C, p & 2 on board Do Practice D, p. 662 on board Herriman High Honors Physics


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