1. Water potential Ψ

2. Ψ = Ψp + Ψs
Ψp = pressure potential
Ψs = solute potential

3. A cell is in equilibrium with its surroundings
A cell is in equilibrium with its surroundings. The molarity of the surrounding solution is 0.5M
To convert molarity to solute potential in MPa (bars), use the formula: ΨS = - ( i CRT ) where
i = ionization constant (assume that is 1)
C=molar concentration (given above)
R = pressure constant (R = liter bars/mole K)
T = temp. in Kelvin (room temp is about 273 K° + 20 C°)
Calculate the solute potential of the surrounding solution.
Find the water potential of the surrounding solution.
What is the water potential of the cytoplasm of the cell?

4. Two identical cells are place in two different environments
Two identical cells are place in two different environments. The cells both have a Ψ = -.7. One in distilled water the other .4M. What happens?
ΨS = - ( i CRT ) where
i = ionization constant (assume that is 1)
C=molar concentration (given above)
R = pressure constant (R= liter bars/mole K )
T = temp. in Kelvin (room temp is about 293 °K )