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8 Integration Techniques, L’Hôpital’s Rule, and Improper Integrals
Copyright © Cengage Learning. All rights reserved.
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Copyright © Cengage Learning. All rights reserved.
8.8 Improper Integrals 2015 Copyright © Cengage Learning. All rights reserved.
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Warm-Up Evaluate the limit:
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Objectives Evaluate an improper integral that has an infinite limit of integration. Evaluate an improper integral that has an infinite discontinuity.
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Improper Integrals The definition of a definite integral
requires that the interval [a, b] be finite, and that f be continuous on [a, b]. This section examines a procedure for evaluating integrals that do not satisfy these requirements—usually because either one or both of the limits of integration are infinite, or f has a finite number of infinite discontinuities in the interval [a, b]. Integrals that possess either property are said to be improper integrals.
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Improper Integrals with Infinite Limits of Integration
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Consider the integral This can be interpreted as the area of the shaded region in the figure: Now, taking the limit as The integral converges to 1.
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Example 1 – An Improper Integral
Evaluate Solution:
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Example 1 – Solution cont’d
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Example 2 – Improper Integrals
Evaluate each improper integral: Solution:
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Example 3 – Using L’Hopital’s with an Improper Integral
Evaluate: Now apply the definition of an improper integral: Using L’Hopital’s on the limit:
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Example 4 – Infinite upper and lower limits of integration
Evaluate: Convenient breaking point? Solution:
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You try Evaluate:
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Improper Integrals with Infinite Limits of Integration
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Homework Day 1: Section 8.8 pg #1-31 odd
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Improper Integrals with Infinite Discontinuities
Day 2 Improper Integrals with Infinite Discontinuities
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Try this: Find the area of: Graph? To find the area under a curve that is discontinuous on the interval, divide the region at the discontinuity and compute the areas of the sub-regions. The area is infinite between -1 and 1.
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Improper Integrals with Infinite Discontinuities
A function f is said to have an infinite discontinuity at c if, from the right or left,
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Improper Integrals with Infinite Discontinuities
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Example 6 – An Improper Integral with an Infinite Discontinuity
Evaluate Solution: The integrand has an infinite discontinuity at x = 0, as shown in Figure 8.24. You can evaluate this integral as shown below. Figure 8.24
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Example 7 – An Improper Integral
Evaluate Solution:
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If you don’t check to see that the integral is improper,
Example 8 – Try this one Evaluate Solution: The integral is improper because it has an infinite discontinuity at an interior point. Rewrite as If you don’t check to see that the integral is improper, you’ll arrive at 3/8, which is incorrect.
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Example: (P is a constant.) What happens here? If then gets bigger and bigger as , therefore the integral diverges. If then b has a negative exponent and , therefore the integral converges.
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Improper Integrals with Infinite Discontinuities
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Example 11 – An Application Involving A Solid of Revolution
The solid formed by revolving (about the x-axis) the unbounded region lying between the graph of f(x) = 1/x and the x-axis (x ≥ 1) is called Gabriel’s Horn. (See Figure 8.28.) Show that this solid has a finite volume and an infinite surface area. Figure 8.28
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Example 11 – Solution Using the disk method and Theorem 8.5, you can determine the volume to be The surface area is given by
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Example 11 – Solution Because
cont’d Because on the interval [1, ), and the improper integral diverges, you can conclude that the improper integral also diverges. So, the surface area is infinite.
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Homework Day 1: Section 8.8 pg. 585 #1-31 odd Day 2: Section 8.8 pg. 585 #33-49odd, 50, 53, 55, 67. Day 3: MMM 121,122,124
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