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Published byTrevor Griffith Modified over 9 years ago
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7.1 Integral as Net Change Objective: SWBAT solve problems in which a rate is integrated to find the net change over time in a variety of applications
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Distance vs Displacement The position of a function can be found by taking the integral of the velocity function. The change in position is a displacement (difference between starting and ending points). To see the difference between distance and displacement, consider the following saying: “Two steps forward and one step back.” What is the total distance traveled? – 3 steps What is the total displacement? – 1 step forward Integrals will give you the total change in displacement. To get total distance, you would need to incorporate something like absolute value.
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We had both positive (moved right) and negative (moved left) velocity, so what’s the change in position? We are 4 spaces to the right further than what we started with.
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Total distance means we want the total area. Thinking about this as if we are taking steps, essentially Johnny Particle took 5 steps forward and 1 step back.
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To find out how much sand is removed, just integrate the removal function from [0,6].
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We have to some variable other than t since when we integrate we want the expression to be in terms of t (substitute in a t)
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Remember that minimum values can occur at endpoints, or when the derivative is 0.
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