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J Unit 3 Chemical Reactions 3.5 What is a mole? February 14, 2010 Do Now: Balance equations if needed. Explain why the following reaction will or Will not take place. __ Zn + __ CuSO 4 __ Cu + __ ZnSO 4 AIM : How can we calculate number of moles of a particular substance? The reaction will take place since Zn is Located above Cu on the Activity Series.
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WHAT IS A MOLE? A MOLE is a unit of measurement for the amount of substance A MOLE = 6.023 x 10 23 atoms How much does it weigh? 1 mole of a substance equals to the molecular mass (or atomic mass) of that substance Avogadro’s Number
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STEPSEXAMPLE: CARBON HOW TO FIND HOW MUCH A MOLE OF A SUBSTANCE WEIGHTS? 1. Find the atomic mass of an element (C) 12.01amu 2. The atomic mass (but in grams!) is the mass of 1 MOLE of that Element. (C) 12.01amu 1 MOLE 12.01g 3. If more than one element, the MOLECULAR MASS (but in grams) is the mass of 1 MOLE of that substance. O 2 15.99 x 2 ~ 32 O 2 32amu 32g
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LET’S TRY SOME 2. What is one mole of HCl? H 1amu HCl 1 + 17 = 18amu 18g Cl 17amu
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HOW TO CALCULATE TOTAL NUMBER OF MOLES? REMEMBER: gram-formula mass = molecular mass in grams
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CONVERTING GRAMS TO MOLES STEPSEXAMPLE: How many moles are equivalent to 4.75g of sodium hydroxide (NaOH)? 1.Calculate the gram formula mass of the substance (Na) (O) (H) 23amu 16amu 1amu 23g 16g 1g1g 40g 2. Plug into equation and solve for number of moles (divide mass by gram-formula mass) Moles = given mass (g) Gram-formula mass Moles = 4.75g 40g Moles = 0.11875 mol
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CONVERTING MOLES TO GRAMS STEPSEXAMPLE: How many grams are present in 4.05mol of sulfuric acid (H 2 SO 4 )? 1.Calculate the gram formula mass of the substance (H) (S) (O) 2amu 32amu 84amu 2g2g 32g 84g 118g 2. Plug into equation and solve for mass (Multiply moles by gram formulas mass) Moles = given mass (g) Gram-formula mass 4.05mol = given mass 118g Given mass = 40.5 x 118 = 477.9g
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Complete the Independent Practice -IP will be collected at the end of class!!! -WORK ON UNIT 1 IN THE HOMEOWORK PACKET -Make up LABS!! Come see me if you are missing any -Work on 3.4 Independent Practice from Wednesday…..
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