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Practice 15A Answers 18.5° a) 27.5° b) glycerine (n = 1.47) c) 12.5°

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Presentation on theme: "Practice 15A Answers 18.5° a) 27.5° b) glycerine (n = 1.47) c) 12.5°"— Presentation transcript:

1 Practice 15A Answers 18.5° a) 27.5° b) glycerine (n = 1.47) c) 12.5°

2 Physics 15.1 Refraction of Light and Snell’s Law
What do you notice about the pencil? Physics 15.1 Refraction of Light and Snell’s Law

3 I. Refraction Def – The bending of light as it travels from one medium to another. 1. Must be at an angle other than 90° 2. If 90° then no refraction 3. Occurs when light’s velocity changes Variables 1. Θi = angle of incidence 2. Θr = angle of refraction

4 C. Velocity Changes 1. cause light rays to speed up or slow down 2
C. Velocity Changes 1. cause light rays to speed up or slow down 2. Situations a. High speed  lower speed Result = Light is bent towards the normal

5 b. Low Speed  higher speed Result =
Light is bent away from the normal

6 Concept Question Alaskan Natives When trying to catch a fish, should a pelican dive into the water horizontally in front of or behind the image of the fish it sees? *Answer: Behind of the image, because the light entering the water slows down and is bent towards the normal.

7 E. Barrel Rolling Explanation pg. 563

8 II. The Law of Refraction
Index of Refraction – ratio of speed of light in vacuum to speed of light in a medium. Formula n = c / v a. n = index of refraction b. c = speed of light in vacuum c. v = speed of light in medium Table 15-1 D. Explains a prism

9 III. Snells’s Law Def - the relationship between the angle of incidence and angle of refraction of two materials having different index of refraction. B. Formula n1 sin(Θ1) = n2 sin (Θ2) C. Variables 1. n = indexes of refraction 2. Θ = angles of the rays

10 Ex: A light ray traveling through air strikes a piece of carbon disulfide at an angle of 25.0° to the normal. Find the angle of refraction. 15.0°


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