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Rotational kinematics and energetics
Lecture 18: Rotational kinematics and energetics Angular quantities Rolling without slipping Rotational kinetic energy Moment of inertia Energy problems
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Angle measurement in radians
s is an arc of a circle of radius π Complete circle: π = 2ππ , π=2π
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Angular Kinematic Vectors
Position: ΞΈ Angular displacement: ΞΞΈ= ΞΈ 2 β ΞΈ 1 Angular velocity: Ο π§ = πΞΈ ππ‘ Angular velocity vector perpendicular to the plane of rotation
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Angular acceleration Ξ± π§ = π Ο π§ ππ‘
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Angular kinematics For constant angular acceleration:
Compare constant π π₯ : π= π 0 + π 0π§ π‘ πΌ π§ π‘ 2 π₯= π₯ 0 + π£ 0π₯ π‘+Β½ π π₯ π‘ 2 π£ π₯ = π£ 0π₯ + π π₯ π‘ π π§ = π 0π§ + πΌ π§ π‘ π π§ 2 = π 0π§ πΌ π§ πβ π 0 π£ π₯ 2 = π£ 0π₯ 2 + 2π π₯ (π₯β π₯ 0 )
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Relationship between angular and linear motion
linear velocity tangent to circular path: π£= ππ ππ‘ = π ππ‘ ππ =π ππ ππ‘ π£=ππ π π‘ππ =Ξ±π π πππ = π£2 π = π2 π π distance of particle from rotational axis Angular speed π is the same for all points of a rigid rotating body!
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Rolling without slipping
Rotation about CM Translation of CM Rolling w/o slipping If π£ πππ = π£ πΆπ : π£ πππ‘π‘ππ =0 no slipping π£ πΆπ =ππ
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Rotational kinetic energy
πΎπππ‘ππ‘πππ = β Β½ π π π£ π 2 = βΒ½ π π ( Ο π π π )2 = βΒ½ π π (Ο π π )2 = Β½ [ β π π π π 2 ] π2 πΎπππ‘ = Β½ πΌ π2 πΌ= π π π π π 2 with Moment of inertia
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Moment of inertia πΌ= π π π π π 2 Continuous objects: Table p. 291
πΌ= π π π π π 2 π π perpendicular distance from axis Continuous objects: πΌ= π π π π π 2 βΆ π 2 ππ Table p. 291 * No calculation of moments of inertia by integration in this course.
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Properties of the moment of inertia
1. Moment of inertia πΌ depends upon the axis of rotation. Different πΌ for different axes of same object:
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Properties of the moment of inertia
2. The more mass is farther from the axis of rotation, the greater the moment of inertia. Example: Hoop and solid disk of the same radius R and mass M.
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Properties of the moment of inertia
3. It does not matter where mass is along the rotation axis, only radial distance ππ from the axis counts. Example: πΌ for cylinder of mass π and radius π
: πΌ=Β½ππ
2 same for long cylinders and short disks
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Parallel axis theorem πΌ π = πΌ ππ||π +π π 2 Example:
πΌ π = 1 12 π πΏ 2 +π πΏ 2 2 = 1 12 π πΏ π πΏ 2 = 1 3 π πΏ 2
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Rotation and translation
πΎ= πΎ π‘ππππ +πΎπππ‘ =Β½π π£ πΆπ 2 + Β½ πΌ π2 π£ πΆπ =ππ
with
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Hoop-disk-race Demo: Race of hoop and disk down incline Example: An object of mass π, radius π
and moment of inertia πΌ is released from rest and is rolling down incline that makes an angle ΞΈ with the horizontal. What is the speed when the object has descended a vertical distance π»?
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