1. Warm ups 1. The relation defined by the set of ordered pairs below is not a function. Which pair could be removed to obtain a function?? {(-5,1) (2,3) (1,6) (-5,8) (7,3)} 2.Solve x + 2y = 4 if the domain is {-4,0,4}

2. Homework Questions? And Return Quizzes

3. 5-5 Functions Objective: To find the value of a function for a given element of the domain. Standard 16.0

4. Functional Notation f(x) Read: “f of x” Means: a function involving x Equals: y

5. Example 1 Given f(x) = 3x + 2, solve for f(2) = 3(2) + 2 6 + 2 8 f(w) =3(w) + 2 3w + 2 Steps: 1.Replace any “x” with the new item inside the parenthesis (plug it in, plug it in!! ) 2.Only work with the right side of the equation

6. Example 1 continued f(x) = 3x + 2 f(w + 1) = 3(w + 1) + 2 3w + 3 + 2 3w + 5 2f(3) =2[3(3) + 2] 2(9 + 2) 2(11) 22 Distribute!PEMDAS

7. Try On Own g(x) = x – 2x 2 g(1) = g(3) =-15 g(-2) =-10

8. Example 2 h(x) = 4 - 2x h(1/2) = 4 – 2(1/2) 4 – 1 3 h(w – 3) =4 – 2(w – 3) 4 – 2w + 6 10 – 2w

9. Example 2 continued h(x) = 4 - 2x 3h(1) = 3[4-2(1)] 3(4 – 2) 3(2) 6 g(3) + 5 =[4 – 2(3)] + 5 (4 – 6) + 5 -2 + 5 3 PEMDAS!

10. Try On Own f(x) = 3x 2 f(2) = 12 3f(-1) =9 f(0) =0 f(-2) =12

11. Homework 5-5 Practice