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SOLVING EQUATIONS INVOLVING ABSOLUTE VALUE LESSON 2-5.

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Presentation on theme: "SOLVING EQUATIONS INVOLVING ABSOLUTE VALUE LESSON 2-5."— Presentation transcript:

1 SOLVING EQUATIONS INVOLVING ABSOLUTE VALUE LESSON 2-5

2 QUICK REVIEW SOLVE THE FOLLOWING: 8y + 3 = 5y + 154(x+3) – 14 = 7 ( x-1) 2.8w – 3 = 5w – 0.85(x + 3) + 2 = 5x + 17

3 TRY THESE: An even integer divided by 10 is the same as the next consecutive even integer divided by 5. What are the two integers? Solve 12w + 4(6-w) = 2w + 60

4 *EVALUATE ABSOLUTE VALUE EXPRESSIONS *ABSOLUTE VALUE EQUATIONS Absolute value means distance from______. The term inside the absolute signs are always_________ |12||-12| -|12| |a-7| + 15 if a = 5

5 SPECIAL CASE Solve |p + 6 | = -5 Then graph the solution set Solve |2x + 3| = 5 Graph the solution

6 REAL WORLD EXAMPLE The average January temperature in a northern Canadian city is 1ºF. The actual January temperature for that city may be about 5ºF warmer or colder. Write and solve an equation to find the maximum and minimum temperatures. Method #1- Graphing: Method #2- Compound Sentence

7 TRY THIS ONE: Evaluate |17-b| + 23 if b= 6 Key Concept: Words: When solving equations that involve absolute values there are two cases to consider. Case1: The expression inside the absolute value symbol is positive. Case 2: The expression inside the absolute value symbol is negative. Symbols For any real numbers a and b, if |a| =b, then a=b or a = -b. Example: |d| = 10, so d = _______ or d = _______

8 SOLVING EQUATIONS WITH ABSOLUTE VALUE Solve |2x – 1 | = 7. Then graph the solution set. |x – 3| = -5

9 TRY THIS ONE: The average temp0erature for Columbus on Tuesday was 45º The actual temperature for anytime during the day may have actually varied from the average temperature by 15º. Solve to find the maximum and minimum temperatures.

10 WRITE AN ABSOLUTE VALUE EQUATION Write an equation involving absolute value for the graph. 6

11 WRITE AN EQUATION INVOLVING THE ABSOLUTE VALUE FOR THE GRAPH 6 A.|x – 2| + 4 B.|x + 2| = 4 C.|x – 4| = 2 D.|x + 4| = 2 |


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