1. Volts per division = 2 V Peak Voltage = 1.5 x 2 = 3 V Volts per division = 5 mV Volts per division = 20 V Peak voltage = 3 x 5 = 15 mV ( 0.015 V) Peak voltage = 1.5 x 20 = 30 V

2. 12 V 3 1.5 3 5 1. What is this meter measuring? 2. What is the current going through the bulb? 3. If both resistors are identical, what current is going through each? 4. How would you measure the voltage across a bulb? 5. What would be the voltage across each resistor? 7

3. 1 Energy = 2kJTime = 5 sPower = ? 2 Current = 2 AVoltage = 2VResistance = ? 3 Current = 15 ATime = 120 sCharge = ? 4 Voltage = 12 VCurrent = 0.5 AResistance 5 Charge = 13 CTime = 2 minutesCurrent = ? 6 Current = 25 mAPower = 1000WVoltage = ? 7 Power = 1000 WTime = 150 sEnergy = ? 10  8. Find the resistance (a) 10  (b) (c) X 4  Y 12  Y 10 Ω 20 Ω (d)

4. 1.P = E ÷ t = 2000 ÷ 5 = 40 W 2. R = V ÷ I = 2 ÷ 2 = 1 Ω 3. Q = It = 15 x 120 = 1800 C 4. R = V ÷ I = 12 ÷ 0.5 = 24  5. I = Q ÷ t = 13 ÷ 120 = 0.11 A 6. V = P ÷ I = 1000 ÷ 0.025 = 40 000 V 7. E = Pt = 1000 x 150 = 150 000J 8. (a) R t = R 1 + R 2 = 10 + 10 = 20  (b) 10 ÷ 2 = 5  (c) 1/R T = 1/R 1 +1/R 2 = ¼ + 1/12 = 0.25 + 0.08333= 0.333 R T = 1/0.333 = 3  (d) 1/R T = 1/R 1 +1/R 2 = 1/20 + 1/10 = 0.05 + 0.1= 0.15 R T = 1/0.15 = 6.7  add to series part 6.7 + 20 = 26.7 Ω