1. Oracle 11g DATABASE DEVELOPMENT LAB2

2. Chapter- 2  These commands, which could be issued from SQL*Plus or SQL Developer,  will make it possible to log on as users HR and OE using the passwords HR and OE:  alter user hr account unlock identified by hr;  alter user oe account unlock identified by oe;.  Now login to sqlplus using the user name and password  Hr

3. Chapter- 2  Arithmetic expression to calculate number of days worked.

4. Chapter- 2 .. Use of the concatenation and arithmetic operators

5. Chapter- 2 .. Use of column and expression aliases

6. Chapter- 2 .. Use of the AS keyword to specify column aliases

7. Chapter- 2 .. Null values in the Commission_Pct column

8. Chapter- 2 .. Null arithmetic always returns a null value.

9. Chapter- 2 . Question 1: It was demonstrated earlier how the number of days for which staff were employed in a job could be calculated. For how many years were staff employed while fulfilling these job roles and what were their EMPLOYEE_ID, JOB_ID, START_DATE, and END_DATE values? Alias the expression column in your query with the alias Years Employed. Assume that a year consists of 365.25 days.  select employee_id, job_id, start_date, end_date,  ((end_date-start_date) + 1)/365.25 "Years Employed"  from job_history;

10. Chapter- 2 ..

11. .. select 'The Job Id for the '||job_title||'''s job is: '||job_id AS "Job Description“ from jobs;

12. Chapter- 2 .. Character column-based WHERE clause

13. Chapter- 2 .. Equivalence of conditional expressions

14. Chapter- 2  Statement 1:  select employee_id from job_history  where start_date = end_date;  Statement 2:  select employee_id from job_history  where start_date = '01-JAN-2001';  Statement 3:  select employee_id from job_history  where start_date = '01-JAN-01';  Statement 4:  select employee_id from job_history  where start_date = '01-JAN-99';.

15. Chapter- 2 .. Using the WHERE clause with numeric expressions

16. Chapter- 2 .. Conditions based on the equality operator

17. Chapter- 2 .. Conditions based on the inequality operators

18. Chapter- 2 select last_name from employees where salary between 3400 and 4000; select last_name from employees where salary >= 3400 and salary <= 4000; select first_name, hire_date from employees where hire_date between '24-JUL-1994' and '07-JUN-1996'; select first_name, hire_date from employees where '24-JUL-1994' between hire_date+30 and '07-JUN-1996';.

19. Chapter- 2 select last_name from employees where salary in (1000,4000,6000); select last_name from employees where salary = 1000 OR salary = 4000 OR salary = 6000; select last_name from employees where last_name in ('King','Garbharran','Ramklass'); select last_name from employees where hire_date in ('01-JAN-1998','01-DEC-1999');.

20. Chapter- 2 select first_name from employees where first_name like 'A%'; where first_name like '%'; where last_name like 'King'; where last_name = 'King'; . Pattern Comparison with the LIKE Operator

21. Chapter- 2 ..