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Published byMelvin Barber Modified over 9 years ago
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Draining the Antifreeze A Very Confusing Mixture Problem
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The Problem Your car can hold 12 liters of anti-freeze. It currently has a 10% antifreeze solution. Winter is on the way! How much antifreeze do you need to drain and replace with pure antifreeze to make it a 25% solution?
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The Confusion 1.Drain? We have only done problems where we add things together. Drain? What am I supposed to do with drain? 2.Pure antifreeze? Why did they say pure antifreeze?
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The Confusion 1.Drain? 1.We are mentally going to drain all the antifreeze and put it in a pail. 2.Then we’re going to add antifreeze from the pail and some pure antifreeze. 3.Voila! - a familiar mixture problem. 2.Pure anti-freeze? The percentage of antifreeze in pure anti-freeze is 100%.
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Let’s make our boxes # liters % Liters antifreeze old mixx1010x Pure12 - x100100( 12 – x) New mix1225300
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Let’s make our equation 10x + 100( 12 – x) = 300 Liters antifreeze Antifreeze in old mix10x Antifreeze in pure100( 12 – x) Antifreeze in new mix300
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Now let’s solve 10x + 100( 12 – x) = 300 10x + 1200 - 100x = 300 - 90x = 300 – 1200 - 90x = - 900 x = 10
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Now let’s check We’ve kept 10 liters of our old 10% solution. That’s 1 liter of antifreeze. We have 2 liters of the pure stuff. That’s 2 liters of antifreeze. 1 + 2 = 3 liters of antifreeze. We wanted 25% of the 12 liters to be antifreeze. 25% of 12 =.25 ( 12 ) = 3 Hooray!
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Don’t Allow Brain Drain! Drain? Drain it all into a pail and mix it back in like a regular problem. Pure Antifreeze? 100% antifreeze
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