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Quiz Answers 38. Degree = 2 36. Degree = 4 40. Degree = 5 41. Degree = 6 42. Degree = 4 43. Degree = 7 44. 3x 4 + x 2 – x – 5 45. -4x 4 + 5x 3 y – 2x 2.

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Presentation on theme: "Quiz Answers 38. Degree = 2 36. Degree = 4 40. Degree = 5 41. Degree = 6 42. Degree = 4 43. Degree = 7 44. 3x 4 + x 2 – x – 5 45. -4x 4 + 5x 3 y – 2x 2."— Presentation transcript:

1 Quiz Answers 38. Degree = 2 36. Degree = 4 40. Degree = 5 41. Degree = 6 42. Degree = 4 43. Degree = 7 44. 3x 4 + x 2 – x – 5 45. -4x 4 + 5x 3 y – 2x 2 y 3 + xy – 27 46. -3x 3 + x 2 – 5x + 5 47. 4x 2 – 5xy + 6y 2 48. 4z 2 – 2z + 10 49. 21m 4 – 10m – 1 Agenda 1.Review quiz (10 min) 2.Quiz corrections (10 min) 3.Simplifying and Solving Equations Review (on tablets) (15 min) 4.Back of agenda problems (for homework)

2 Wed, 5/10/10 SWBAT…multiply two binomials using the FOIL method Agenda 1. WU (5 min) 2. Review simplifying and solving equations (15 min) 3. Review hw#3 (10 min) 4. Practice – Multiplying two binomials (20 min) Warm-Up: Write your hw in your planner for the week!

3 1/10 Simplify the following expression by combining like terms: 3x – 5 – 7x + 9 A. -4x – 4 B. 4x + 4 C. -4x + 4D. 10x + 4

4 2/10 Simplify the following expression by using the distributive property: 5(n + 1) A. n + 1B. 5n + 1C. 5n + 5 D. 5n + 6

5 3/10 Simplify the following expression by using the distributive property: -6(3x – 2) A. -18x + 6 B. -18x – 12C. -18x + 12 D. -18x – 6

6 4/10 Solve for z: 7z – 4 = 10 A. -2B. -1C. 1D. 2

7 5/10 Solve for z: –2z + 1 = -9 A. 5B. -5C. 4D. -4

8 6/10 Solve for x: – 5 = 3 A. 12B. -12C. 3D. -3

9 7/10 Solve for y: 5y + 9 + 2y = 23 A.1B. 2C. 3 D. 4

10 8/10 Solve for y: 6y + 2 = y + 17 A. 3B. 4C. 5D. 6

11 9/10 Solve for k: 2 + 5k = 3k – 6 A. -4B. -5C. 4D. 5

12 10/10 Solve for q: -5(3 – q) + 4 = 5q – 11 A. 15B. -15C. No Solution D. Infinite Solution

13 If you got <70%, then you need to do the back of the agenda problems! DUE TOMORROW!!!! If you need help, you know where we are!

14 Mon, 5/10/10 SWBAT…multiply two binomials using the FOIL method Agenda 1. WU (10 min) 2. Review hw#3 (10 min) 3. Notes on multiplying two binomials (FOIL) (5 slides) Warm-Up: 1. Simplify: 3ab(5a 2 – a – 2) + 2a(b + 1) 2. Solve for c: 3(2c – 3) – 1 = -4(2c + 1) + 8 3. Solve for w: 5(9w + 2) = 3(8w – 7) + 17 HW#4: Multiplying two binomials

15 Additional Practice Problems 1.) 2(4x – 7) = 5(-2x – 9) – 5 2.) Solve: 9c(c – 11) + 10(5c – 3) = 3c(c + 5) + c(6c – 3) – 30 3.) Solve: 2k(-3k + 4) + 6(k 2 + 10) = k(4k + 8) – 2k(2k + 5) 4.) d(d – 1) + 4d = d(d – 8) Answers: 1. x = -2 2. c = 0 3. k = -6 4. No Solution

16 Open to page 543 in the books Read the example from hw#4

17 Multiply two binomials using FOIL method To multiply two binomials, find the sum of the products of: F the First terms O the Outer terms I the Inner terms L the Last terms (x + 3)(x + 2) FL I O

18 Observations The expression ( x + 3)( x + 2) is read as “the quantity of x plus 3 times the quantity of x plus 2” FOIL is a memory tool, the order in which the terms are multiplied is not important, as long as four products are found. Notice that when the two linear expressions are multiplied, the result is a quadratic (degree 2).

19 Multiply two binomials using FOIL method (x + 3)(x + 2) F L O = (x)(x) FLIO I + (x)(2)+ (3)(x)+ (3)(2) = x 2 + 2x + 3x + 6 = x 2 + 5x + 6 To multiply two binomials, find the sum of the products

20 Find each product: 1. (x + 4)(x – 2) 2. (2y – 7)(3y + 5) Answer: 6y 2 – 11y – 35 3. (4a – 5)(2a – 9) Answer: 8a 2 – 46a + 45 = (x)(x) + (x)(-2)+ (4)(x)+ (4)(-2) = x 2 – 2x + 4x – 8 = x 2 + 2x – 8 F L O I

21 Find each product: 2. (2y – 7)(3y + 5) 3. (4a – 5)(2a – 9) Answer: 8a 2 – 46a + 45 = (2y)(3y)+ (2y)(5) + (-7)(3y)+ (-7)(5) = 6y 2 + 10y – 21y – 35 = 6y 2 – 11y – 35 F L O I

22 Exit Slip 1. (x + 2)(x + 4) 2. (2x + 3)(4x – 5)

23 Wed, 4/12/10 SWBAT…multiply two binomials using the FOIL method Agenda 1. WU (10 min) 2. Review hw#4 (10 min) 3. Special products (hw#5) Warm-Up: Multiply each binomial 1.) (2a – 5)(3a + 5) 2.) (2b – 5)(2b + 5)

24 VOLLEYBALL FYI: teachers beat students 2-0 The dimensions of a volleyball court are represented by a width of 6y – 5 feet and a length of 3y + 4 feet. (a) Write an expression that represents the area of the court. (b) The length of a volleyball court is 31 feet. Find the area of the court.


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