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21.4 Transport properties of a perfect gas
Experimental observations on transport properties shows that the flux of a property is proportional to the first derivative of other related properties. The flux of matter is proportional to the first derivative of the concentration (Fick’s first law of diffusion): J(matter) The rate of thermal conduction is proportional to the temperature gradient: J(energy) J(matter) = D is called the diffusion coefficient (m2s-1); J(energy) = - k dT/dz k is called the coefficient of thermal conductivity (J K-1 m-1 s-1)
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J(x-component of momentum) = , η is the coefficient of viscosity.
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Table 21.3
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Diffusion
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As represented by the above Figure, on average the molecules passing through the area A at z = 0 have traveled about one free path. The average number of molecules travels through the imaginary window A from Left to Right during an interval Δt is ZwA Δt (L→R) Because Zw = So A Δt (L→R) The average number of molecules travels through the imaginary window A from Right to Left during an interval Δt is A Δt (R →L) The net number of molecules passing through the window A along the z direction is: A Δt A Δt By definition the flux of molecules along z direction can be calculate as J(z) = ( A Δt A Δt )/(A Δt ) J(z) = The number density N(-λ) and N(λ) can be represented by number density N(0) at z =0 N(-λ) = N(0) - λ N(λ) = N(0) + λ Therefore: J(z) = then we get D = (different from what we expected)
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A factor of 2/3 needs to be introduced.
So we get D =
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Thermal conduction k = where CV,m is the molar heat capacity at constant volume. Because λ is inversely proportional to the molar concentration of the gas, the thermal conductivity is independent of the concentration of gas, and hence independent of the gas pressure. One exception: at very low pressure, where the mean free path is larger than the size of the container.
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J(x-component of momentum) = , η is the coefficient of viscosity.
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Viscosity The viscosity is independent of the pressure.
Proportional to T1/2
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Measuring the viscosity
Poiseuille’s formula:
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Calculations with Poiseuille’s formula
Example: In a poiseuille flow experiment to measure the viscosity of air at 298K, the sample was allowed to flow through a tube of length 100cm and internal diameter 1.00mm. The high-pressure end was at 765 Torr and the low-pressure end was at 760Torr. The volume was measured at the latter pressure. In 100s, 90.2cm3 of air passed through the tube. Solution: Reorganize Poseuille’s equation:
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