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Mrs. English Fox Creek Jr. High BCESD.  What is an equation?  How are equations useful in solving real- world problems?  How do you solve an algebraic.

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Presentation on theme: "Mrs. English Fox Creek Jr. High BCESD.  What is an equation?  How are equations useful in solving real- world problems?  How do you solve an algebraic."— Presentation transcript:

1 Mrs. English Fox Creek Jr. High BCESD

2  What is an equation?  How are equations useful in solving real- world problems?  How do you solve an algebraic equation?  What is a variable? How do you isolate the variable to solve an equation?

3  We can solve real-world problems using both arithmetic and algebra.  If we use the arithmetic method, we would use only numbers.  If we use the algebra method, we would use numbers and variables (letters)  Either way, we will end up with the same answer.

4  The sum of two different sides of the rectangle is 17 inches. What is the perimeter of the rectangle?

5  I know that perimeter means the distance around something, so I need to find out how far it is around the whole rectangle

6  The sum of two different sides of the rectangle is 17 inches. What is the perimeter of the rectangle?  I know that perimeter means the distance around something, so I need to find out how far it is around the whole rectangle This side and this side add up for a total of 17 inches

7  The sum of two different sides of the rectangle is 17 inches. What is the perimeter of the rectangle?  I know that perimeter means the distance around something, so I need to find out how far it is around the whole rectangle This side and this side add up for a total of 17 inches To find the perimeter, I need to find the distance around the other half of the rectangle.

8  The sum of two different sides of the rectangle is 17 inches. What is the perimeter of the rectangle?  I know that perimeter means the distance around something, so I need to find out how far it is around the whole rectangle This side and this side add up for a total of 17 inches To find the perimeter, I need to find the distance around the other half of the rectangle. 17 x 2 = ? Or 1/2(x) = 17

9  The sum of two different sides of the rectangle is 17 inches. What is the perimeter of the rectangle?  I know that perimeter means the distance around something, so I need to find out how far it is around the whole rectangle This side and this sideadd up for a total of 17 inches To find the perimeter, I need to find the distance around the other half of the rectangle. 17 x 2 = ? Or 1/2(x) = 17 17 x 2 = 34 x 2 x 2 x = 34

10  The sum of two different sides of a rectangle is 24 centimeters. What is the perimeter of the rectangle?

11  A corn field is 500 feet wide. If you know the perimeter is 1600 feet, what is the corn field’s length?

12 Using arithmeticUsing algebra 1600-500-500 = 6001600-2(500)=2x 600 / 2 = 3001600-1000=2x 600 = 2x 300 = x

13  A soybean field is 420 feet wide. If you know the field has a perimeter of 1600 feet, what is the field’s length?

14  Your dog gave birth to 6 puppies. You want to keep them all, but you were told you had to sell all but 1 of them. If you earned $325, how much did each puppy cost?

15  How many puppies did you sell?

16  Your dog gave birth to 6 puppies. You want to keep them all, but you were told you had to sell all but 1 of them. If you earned $325, how much did each puppy cost?  How many puppies did you sell? 5

17  Your dog gave birth to 6 puppies. You want to keep them all, but you were told you had to sell all but 1 of them. If you earned $325, how much did each puppy cost?  How many puppies did you sell? 5 Using arithmeticUsing algebra $325 / 5 = 5x = $325

18  Your dog gave birth to 6 puppies. You want to keep them all, but you were told you had to sell all but 1 of them. If you earned $325, how much did each puppy cost?  How many puppies did you sell? 5 Using arithmeticUsing algebra $325 / 5 = $655x = $325 5 x = $65

19  Your dog gave birth to 6 puppies. You want to keep them all, but you were told you had to sell all but 1 of them. If you earned $325, how much did each puppy cost?  How many puppies did you sell? 5 Using arithmeticUsing algebra $325 / 5 = $655x = $325OR (6-1)x = $325 5 55x = $325x = $65

20  Your dog gave birth to seven puppies. Your mom told you to sell all but one. If you earned $480, how much did you sell each puppy for?

21  Your dad just got his paycheck and decides to pay for you and your three friends to go bowling. It costs $6.00 per person to get in. Bowling shoes cost $2.50 per person to rent. After bowling for awhile, your dad buys a soda for each person. How much does the soda cost if your dad spent a total of $42.00 at the bowling alley?

22  How many people went bowling?

23  Your dad just got his paycheck and decides to pay for you and your three friends to go bowling. It costs $6.00 per person to get in. Bowling shoes cost $2.50 per person to rent. After bowling for awhile, your dad buys a soda for each person. How much does the soda cost if your dad spent a total of $42.00 at the bowling alley?  How many people went bowling? 4

24  Your dad just got his paycheck and decides to pay for you and your three friends to go bowling. It costs $6.00 per person to get in. Bowling shoes cost $2.50 per person to rent. After bowling for awhile, your dad buys a soda for each person. How much does the soda cost if your dad spent a total of $42.00 at the bowling alley?  How many people went bowling? 4  We need to multiply everything by 4.

25 Arithmetic $42 – 4($6) – 4($2.50)= soda Then divide the cost of soda by 4 bowlers Algebra 4($6) + 4($2.50) + 4(s) = $42.00

26 Arithmetic $42 – 4($6) – 4($2.50)= soda $42 – $24 – $10 = soda Then divide the cost of soda by 4 bowlers Algebra 4($6) + 4($2.50) + 4(s) = $42.00

27 Arithmetic $42 – 4($6) – 4($2.50)= soda $42 – $24 – $10 = soda $8= soda Then divide the cost of soda by 4 bowlers $8/4 = $2 Algebra 4($6) + 4($2.50) + 4(s) = $42.00

28 Arithmetic $42 – 4($6) – 4($2.50)= soda $42 – $24 – $10 = soda $8= soda Then divide the cost of soda by 4 bowlers $8/4 = $2 Algebra 4($6) + 4($2.50) + 4(s) = $42.00 $24 + $10 + 4s = $42.00

29 Arithmetic $42 – 4($6) – 4($2.50)= soda $42 – $24 – $10 = soda $8= soda Then divide the cost of soda by 4 bowlers $8/4 = $2 Algebra 4($6) + 4($2.50) + 4(s) = $42.00 $24 + $10 + 4s = $42.00 $34 + 4s = $42.00

30 Arithmetic $42 – 4($6) – 4($2.50)= soda $42 – $24 – $10 = soda $8= soda Then divide the cost of soda by 4 bowlers $8/4 = $2 Algebra 4($6) + 4($2.50) + 4(s) = $42.00 $24 + $10 + 4s = $42.00 $34 + 4s = $42.00 -$34

31 Arithmetic $42 – 4($6) – 4($2.50)= soda $42 – $24 – $10 = soda $8= soda Then divide the cost of soda by 4 bowlers $8/4 = $2 Algebra 4($6) + 4($2.50) + 4(s) = $42.00 $24 + $10 + 4s = $42.00 $34 + 4s = $42.00 -$34 4s = $8s = $2

32  Your mom just got her paycheck and takes you and four friends to play mini golf. It costs $4.50 per person to play, and another $1.50 per person to rent a putter. After a round of mini golf, your mom also buys you each a personal pizza. If she spent $45 altogether, how much did each pizza cost?

33  Harry is making spaghetti. He went to the store and spent $38.00. He bought 4 cans of spaghetti sauce for $2.25 each, 2 boxes of whole wheat pasta for $3.00 each, a block of parmesan cheese for $6.00, and 4 pounds of ground beef. How much did each pound of ground beef cost?

34  4($2.25) + 2($3.00) + 1($6.00) + 4(b) = $38.00

35  Harry is making spaghetti. He went to the store and spent $38.00. He bought 4 cans of spaghetti sauce for $2.25 each, 2 boxes of whole wheat pasta for $3.00 each, a block of parmesan cheese for $6.00, and 4 pounds of ground beef. How much did each pound of ground beef cost?  4($2.25) + 2($3.00) + 1($6.00) + 4(b) = $38.00  $9 + $6 + $6 + 4b = $38.00

36  Harry is making spaghetti. He went to the store and spent $38.00. He bought 4 cans of spaghetti sauce for $2.25 each, 2 boxes of whole wheat pasta for $3.00 each, a block of parmesan cheese for $6.00, and 4 pounds of ground beef. How much did each pound of ground beef cost?  4($2.25) + 2($3.00) + 1($6.00) + 4(b) = $38.00  $9 + $6 + $6 + 4b = $38.00  $21 + 4b = $38.00

37  Harry is making spaghetti. He went to the store and spent $38.00. He bought 4 cans of spaghetti sauce for $2.25 each, 2 boxes of whole wheat pasta for $3.00 each, a block of parmesan cheese for $6.00, and 4 pounds of ground beef. How much did each pound of ground beef cost?  4($2.25) + 2($3.00) + 1($6.00) + 4(b) = $38.00  $9 + $6 + $6 + 4b = $38.00  $21 + 4b = $38.00 -$21 -$21

38  Harry is making spaghetti. He went to the store and spent $38.00. He bought 4 cans of spaghetti sauce for $2.25 each, 2 boxes of whole wheat pasta for $3.00 each, a block of parmesan cheese for $6.00, and 4 pounds of ground beef. How much did each pound of ground beef cost?  4($2.25) + 2($3.00) + 1($6.00) + 4(b) = $38.00  $9 + $6 + $6 + 4b = $38.00  $21 + 4b = $38.00 -$21 -$21 4b = $17

39  Harry is making spaghetti. He went to the store and spent $38.00. He bought 4 cans of spaghetti sauce for $2.25 each, 2 boxes of whole wheat pasta for $3.00 each, a block of parmesan cheese for $6.00, and 4 pounds of ground beef. How much did each pound of ground beef cost?  4($2.25) + 2($3.00) + 1($6.00) + 4(b) = $38.00  $9 + $6 + $6 + 4b = $38.00  $21 + 4b = $38.00 -$21 -$21 4b = $17 4b/4 = $17/4 b = $4.25

40  Moe is making chicken tacos. He spent $15.75 at the store. He purchased 3 tomatoes for $0.75 each, a bag of cheese for $2.50, 2 onions for $0.50 each, two packages of tortillas for $2.50 each, and 2 pounds of chicken. How much did each pound of chicken cost?

41  What is an equation?  Equations are two values that are equal  How are equations useful in solving real- world problems?  Equations can be translated from real-word problems  How do you solve an algebraic equation?  Equations can be solved by isolating the variable  What is a variable? How do you isolate the variable to solve an equation?  A variable is a letter that represents an unknown value. We isolate the variable by performing inverse operations.


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