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Twenty Years of EPT Graphs: From Haifa to Rostock Martin Charles Golumbic Caesarea Rothschild Institute University of Haifa With thanks to my research collaborators: Robert Jamison, Marina Lipshteyn, Michal Stern
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Bell Labs in New Jersey (Spring 1981) John Klincewicz: Suppose you are routing phone calls in a tree network. Two calls interfere if they share an edge of the tree. How can you optimally schedule the calls? The Story Begins
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Bell Labs in New Jersey (Spring 1981) John Klincewicz: Suppose you are routing phone calls in a tree network. Two calls interfere if they share an edge of the tree. How can you optimally schedule the calls? The Story Begins
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Bell Labs in New Jersey (Spring 1981) John Klincewicz: Suppose you are routing phone calls in a tree network. Two calls interfere if they share an edge of the tree. How can you optimally schedule the calls? The Story Begins A call is a path between a pair of nodes. A typical example of a type of intersection graph. Intersection here means “share an edge”. Coloring this intersection graph is scheduling the calls. An Olive Tree Network
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Vertex Intersection Graphs of Paths in a Tree (VPT) Edge Intersection Graphs of Paths in a Tree (EPT) Each vertex v in V(G VPT ) and V(G EPT ) corresponds to a path P v in T. (x,y) E VPT paths P x and P y intersect on at least one vertex in T. (x,y) E EPT paths P x and P y intersect on at least one edge in T. Representation P of paths in a tree T. G VPT ( P ) PcPc G EPT ( P ) a d b c
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For VPT-representation P a and P b intersect. For EPT-representation: P a and P b do not intersect. For both VPT-representation and EPT-representation P a and P b intersect. Vertex and Edge Intersections of Paths
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Theorem. Chordal graphs vertex intersection graphs of subtrees of a tree. [Buneman], [Gavril], [Walter] A graph G is chordal if every cycle of size 4 has a chord, i.e., G has no induced chordless cycles C m for m 4. Chordal Graphs
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VPT Graphs are Chordal EPT Graphs are Not Chordal A path is a subtree, therefore VPT graphs (i.e., path graphs) are chordal. However, EPT graphs may have chordless cycles of any size.
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A First Observation (Cycles) An EPT representation of C 6 called a “6-pie”. 6 3 2 1 4 5 Chordless cycles have a unique EPT representation.
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A First Observation (Cycles) An EPT representation of C 6 called a “6-pie”. 6 3 2 1 4 5 Theorem (Golumbic Jamison 1985): Let P be an EPT representation of G. If G contains a chordless cycle C m (m 4), then P contains an m-pie representing the cycle. Chordless cycles have a unique EPT representation.
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Restricting the degree of the host tree Remark. If m is the maximum degree in T, then the EPT graph has no chordless (m+1) cycles (or larger).
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Restricting the degree of the host tree Remark. If m is the maximum degree in T, then the EPT graph has no chordless (m+1) cycles (or larger). Corollary: If P is an EPT representation of G on a degree 3 tree T. Then G is chordal graph.
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Restricting the degree of the host tree C6C6 a a a b b b c c c d d d Example. The graph C 6 requires degree 5. A 4-pie on a,b,c,d
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Restricting the degree of the host tree C6C6 a a a b b b c c c d d d x x x y y y Example. The graph C 6 requires degree 5. Now add x and y
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A Second Observation (Cliques) Two EPT representations of K 6 called a “claw clique” or “edge clique”. 6 3 2 1 4 5 edge All share a common edge claw All share some edge of the claw
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A Second Observation (Cliques) Two EPT representations of K 6 called a “claw clique” or “edge clique”. 6 3 2 1 4 5 Theorem (Golumbic Jamison 1985): Let P be an EPT representation of G. If G contains a clique K m (m 3), then P contains either a claw or edge for it. Cliques have exactly two possible EPT representations.
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No Kissing The No Kissing Lemma: If P is an EPT representation of G on a tree T, and u is any node of T. We may assume without loss of generality, and without increasing the degree of the tree, that all paths touching u continue through u. No stopping. No kissing u.
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No Kissing The No Kissing Lemma: If P is an EPT representation of G on a tree T, and u is any node of T. We may assume without loss of generality, and without increasing the degree of the tree, that all paths touching u continue through u. No stopping. No kissing u. e c b a d e c b a d Create dummy nodes and shorten a and e
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Degree 3 host trees If P is a deg3 EPT representation of G on a tree T, then applying the No Kissing Lemma construction to all nodes of degree 3 yields a deg3 VPT representation of G.
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Degree 3 host trees If P is a deg3 EPT representation of G on a tree T, then applying the No Kissing Lemma construction to all nodes of degree 3 yields a deg3 VPT representation of G. i.e., deg3 EPT deg3 VPT deg3 EPT chordal EPT Now let’s prove: chordal EPT deg3 EPT
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Degree 3 host trees (continued) Let P be any EPT representation of G on a tree T, and u any node of T of maximum degree d > 3. 1.Assume the no kissing lemma, and let U denote all paths passing through u. 2.Let x be a simplicial vertex of the induced subgraph G U. Thus, all paths in U share an edge with P x. 3.Perform the transformation: 4.Repeat for all nodes until max degree is 3. x y z x y z
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Degree 3 host trees (continued) Theorem (1985): All four classes are equivalent: chordal EPT deg3 EPT VPT EPT deg3 VPT What about degree 4?
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Degree 3 host trees (continued) Theorem (1985): All four classes are equivalent: chordal EPT deg3 EPT VPT EPT deg3 VPT Theorem (2005, Golumbic, Lipshteyn, Stern): weakly chordal EPT deg4 EPT Degree 4 host trees
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Definition Weakly Chordal Graph No induced C m for m 5, and no induced C m for m 5. Theorem [Hayward, Hoàng, Maffray 1989] G is weakly chordal if and only if every induced subgraph of G is either a clique or has a two-pair. Weakly Chordal Graphs
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A two-pair is a pair of vertices, such that every chordless path between them has length two edges. Remark. If {x,y} is a two-pair, then the common neighborhood of x and y is an (x,y)-minimal separator. {x,y} is a two-pair{x,y} is not a two-pair
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Theorem [GLS 2005] A graph G has an EPT representation on a degree 4 tree if and only if G is a weakly chordal EPT graph. Degree 4 Trees Sketch of the proof. ( ) By the Pie Theorem, G has no induced C m (m 5) nor C 5 (=C 5 ). By our earlier example, C 6 requires degree 5. By a theorem of Golumbic and Jamison 1985, C m (m 7) is not an EPT graph.
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Degree 4 Trees (continued) ( ) Let P be an EPT representation of G on tree T with maximal degree d > 4, and let u be a node of degree d. We transform P into an EPT representation P´ on T´ with fewer vertices of degree d. The full proof follows by induction. Assume the no kissing lemma at u, and let U denote all paths passing through u. The induced subgraph G U is weakly chordal, so there are two cases: G U is a clique or G U has a two-pair.
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Degree 4 Trees (continued) Case 1. G U is a clique. If it were a claw clique, then u would have degree 3, and we are done. Otherwise, G U is an edge clique, and all paths in U share an edge, say (v 1,u). Perform the transformation: v1v1 v1v1 v2v2 v2v2
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Degree 4 Trees (continued) Case 2. G U has a two pair {x,y}. The common neighborhood S of {x,y} is a minimal separator and splits G U into (at least) 2 connected components: G X containing x and G Y containing y. The star edges centered at u, are now painted. The two contained in P x are red; those in P y blue. Propagate the coloring to other star edges via the paths P z (z U \ S): if P z has one red edge, then paint its other star edge red; if P z has one blue edge, then paint its other star edge blue. No star edges gets two colors!
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Degree 4 Trees (continued) Subcase 2a. G S is a clique. Perform the transformation: S
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Degree 4 Trees (continued) Subcase 2b. G S is not a clique. There exists a path P v (v U \ S) that contains only one of the edges (v 1,u),(v 2,u), (v 3,u),(v 4,u), say (v 1,u). Let be the non- empty collection of such paths, which thus form an edge clique containing (v 1,u). Color the star edges as follows: S
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Subcase 2b, continued. 1. (v 1,u) is not colored. 2. (v i,u), i 5 is colored pink if it is contained in a path in . 3. (v i,u) is colored if is contained in a path that already has a pink edge. Lemma: The edges of P y are not colored. Example. [v 1,u,v 5 ] P 1 [v 1,u,v 7 ] P 2 [v 5,u,v 6 ] P 3 = {P 1,P 2 } Q.E.D.
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From Haifa to Rostock (Spring 1985?) The Story Continues
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Algorithmic Aspects of EPT Graphs The recognition and coloring problems of an EPT graph are NP-complete (Golumbic and Jamison, 1985). There is a 3/2-approximation algorithm for coloring EPT graphs. (Tarjan, 1985) On deg3EPT or deg4EPT graphs, coloring is polynomial since, respectively, they are chordal (GJ 1985) or weakly chordal (GLS 2005). Max-clique and Max-stable set are polynomial (GJ 1985).
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[h,s,t] Graphs and Representations A collection of subtrees of a tree T satisfying: h:T has maximum vertex degree h s:Each subtree has maximum vertex degree s t:An edge (x,y) in G if T x and T y share t vertices
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Interval graphs [2,2,1] EPT [ , 2, 2] Chordal graphs [ , ,1] [3,3,1] [3,3,2] (MS,JM) [h,s,t] Graphs and Representations A collection of subtrees of a tree T satisfying: h:T has maximum vertex degree h s:Each subtree has maximum vertex degree s t:An edge (x,y) in G if T x and T y share t vertices
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Interval graphs [2,2,1] EPT [ , 2, 2] Chordal graphs [ , ,1] [3,3,1] [3,3,2] (MS,JM) Any graph [ , ,2] [ ,2,2] chordal [3,2,2] [3,2,1] (GJ) [ ,2,2] weakly chordal [4,2,2] (GLS) [h,s,t] Graphs and Representations A collection of subtrees of a tree T satisfying: h:T has maximum vertex degree h s:Each subtree has maximum vertex degree s t:An edge (x,y) in G if T x and T y share t vertices
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Two Directions to Generalize EPT 1.Keep t = 2 (edge intersection) Increase s (generalizing to subtrees) but Bound max degree h. 2.Increase t (constant tolerence) Keep s = 2 (paths)
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A New Characterization Theorem Golumbic, Lipshteyn, Stern [WG2006]: The class [4,4,2]-graphs is equivalent to weakly chordal (K 2,3, P 6, 4P 2, P 2 P 4, H 1, H 2, H 3 )-free. K 1 and K 2 are cliques of size at most 2.
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Forbidden Subgraphs
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Definition of k-EPT Graphs The k-Edge Intersection Graphs of Paths in a Tree (x,y) E paths P x and P y intersect on at least k edges in T. Def. G is a k-EPT graph if G has a k-EPT representation. k-EPT representation tree T of G G = (V,E) for k = 4 edges k-EPT [ , 2, k+1] (i.e., share k+1 vertices)
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Examples of Intersections For VPT representation: paths a and b intersect. For k-EPT representation, k>0: paths a and b do not intersect. For VPT and 1-EPT representation: paths a and b intersect. For k-EPT representation, k>1: paths a and b do not intersect. For VPT and k-EPT representation, k 4: paths a and b intersect. For k-EPT representation, k>4: paths a and b do not intersect.
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Properties of k-EPT 1-EPT k-EPT, for any fixed k > 1. - Divide each edge into k edges, by adding k-1 dummy vertices. When restricted to degree 3 trees, the containment is also strict. 1-EPT k-EPT, for any fixed k > 1.
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New Properties of k-EPT VPT graphs are incomparable with k-EPT graphs, for any fixed k 1. When restricted to degree 3 trees, VPT k-EPT, for any fixed k 2. Chordless cycles are degree 3 k-EPT for k 2.
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Recognition of k-EPT Important Properties Any maximal clique of a k-EPT graph is either a k-edge clique or a k-claw clique. A k-EPT graph G has at most maximal cliques. k-edge clique k-claw clique
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Recognition of k-EPT Branch Graphs Definition: Let C be a subset of vertices of G. The branch graph B(G/C): G B(G/C) Theorem: Let C be a maximal clique of a k-EPT graph G. Then the branch graph B(G/C) can be 3-colored.
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Recognition of k-EPT NP-Completeness Theorem: It is an NP-complete problem to decide whether a VPT graph is a k-EPT graph. Proof: An arbitrary undirected graph H is 3-colorable iff a certain graph G=(V,E) is a k-EPT graph. H T P ij path in T (i,j) E(H) Q i edge in T i V(H)
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{P ij } corresponds to a maximal clique C of the VPT graph G. B(G/C) is isomorphic to H. If G is VPT and k-EPT H is 3-colorable If H is 3-colorable and G is VPT G is VPT and 1-EPT G is k-EPT. Therefore, G is VPT and k-EPT G is VPT and H is 3-colorable T HP ij path in T (i,j) E(H) Q i edge in T i V(H)
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Recognition of k-EPT Corollaries Corollary: Recognizing whether an arbitrary graph is a k-EPT graph is an NP-complete problem. Corollary: Let G be a VPT graph. Then G is a 1-EPT graph iff G is a k-EPT graph, (hence: iff G is chordal).
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Coloring of k-EPT Theorem: The problem of finding a minimum coloring of a k-EPT graph is NP-complete. Same proof as Golumbic & Jamison (1985) for the case k = 1.
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Forbidden Subgraph Theorem: The following graph is not a k-EPT graph, for any fixed k > 1.
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Open Problem The relationships between k-EPT graphs and (k+1)-EPT graphs, for any fixed k. Is k-EPT (k+1)-EPT? We have graphs that are not 1-EPT but are a (k+1)-EPT graph, for any fixed k.
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C 4 is not VPT but is k-EPT k 1
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D is k-EPT k 2 is not 1-EPT Graph D
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Orthodox Representations P A representation for G is orthodox if For each path, its endpoints are leaves (leaf generated), and Two paths P i, P j share a leaf if and only if vertices i and j are adjacent in G.
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Subtrees of a Tree (i) (ii) (iii) McMorris & Scheinerman 1991 (iv) (v) Jamison & Mulder 2000 ( , ,1 )
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Orthodox Representations orth( ,2,1) orth(3,2,1) orth(3,2,2) Theorem 6.8
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The Complete Heirarchy
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6.4 6.7 6.8
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The Complete Heirarchy
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More on Algorithmic Graph Theory
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Further Research Characterize families of [h,s,t] graphs for various values of h, s and t. Find intersection models as (h,s,t)-representations for known families of graphs. weakly chordal [?, ?, ?]
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Thank You!
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