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1 Overview of C++ CS3304 - Data Structure. 2 Value parameters int abc (int a, int b, int c) // a, b, and c are the { // formal parameters a = a * 2; return.

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Presentation on theme: "1 Overview of C++ CS3304 - Data Structure. 2 Value parameters int abc (int a, int b, int c) // a, b, and c are the { // formal parameters a = a * 2; return."— Presentation transcript:

1 1 Overview of C++ CS3304 - Data Structure

2 2 Value parameters int abc (int a, int b, int c) // a, b, and c are the { // formal parameters a = a * 2; return a+b+c; } call: z = abc(2, x, y) //2, x, y are the actual parameters

3 3 Template Functions float abc (float a, float b, float c) { a = 2 * a; return a+b+c; } template T abc(T a, T b, T c) { a = 2 * a; return a+b+c; }

4 4 Reference Parameters float abc(int& a, int& b, int& c) { a = 2 * a; return a+b+c; } template T abc (T& a, T& b, T& c) { a = 2 * a; return a+b+c; }

5 5 Const Reference Parameters Formal parameters are not changed, avoid copying template T abc (const T& a, const T& b, cont T& c) { return a+b+c; } template Ta abc(const Ta& a, const Tb& b, const Tc& c) { return a+b+c }

6 6 Return Values Value return T X(int i, T& z) // a copy of the value is returned reference return T& X(int i, T& z) //a reference is returned const reference return const T& X(int i, T& z) // a reference to a const // object is returned

7 7 Recursive functions When a function calls itself (directly or indirectly). ex:factorial, exponentiation, and Fibonacci numbers n! = 1 * 2 * 3 *... *n,for n > 0 and that 0! = 1 a recursive function has two parts:  base part  recursive part

8 8 ex: Factorial n! = 1ifn = 0(base) n! = n(n-1)!ifn > 0(recursive )

9 9 Definition Recursion is a problem solving tool that allows you to solve a problem p by solving another problem p' that is similar in nature to p but smaller. Each successive recursive call should bring you closer to a situation in which the answer is known. A case for which the answer is known (and can be expressed without recursion) is called a base case. Each recursive algorithm must have at least one base case, as well as the general (recursive) case

10 10 Factorial N factorial n n! = n * (n - 1) * (n - 2) *... * 2 * 1; int function fact (int n) { if (n == 0) // base case return (1); else// recursive case return (n * fact (n - 1)); }

11 11 Steps fact(4) -> 4 * fact(3) -> 3 * fact(2) -> 2 * fact(1) -> 1 * fact(0) 1 * 1 2 * 1 <-----------| 3 * 2 <-----------| 4 * 6 <------------| 24 <-------|

12 12 iterative solution to factorial int function fact_it (int n ) { int p; p = 1; for (int i = 1; i <= n; i++) p = p * i; return (p); }

13 13 Disadvantages and Advantages of recursion Disadvantages: each function call creates an activation record in memory & requires processing time to set up records & to reset values after return from function call advantages: some problems may be easier to set up & program

14 14 Iterative function for SUM Template T sum(T a[], int n) { //return sum of numbers a[0: n-1] T tsum = 0; for (int i = 0; i< n; i++) tsum += a[i] return tsum; }

15 15 Recursive function for SUM Template T Rsum(T a[], int n) { // return sum of numbers a [0 : n-1] if (n > 0) return Rsum(a, n-1) + a[n-1] return 0; // base case }

16 16 Recursive function for the Fibonacci numbers F(0) = 0 F(1) = 1 F(n) = F(n-1) + F(n-2) int fibonacci(int n) { if (n==0) return 0; else if (n==1) return 1; else if (n > 1) return (fibonacci(n-1) + fibonacci(n-2)); }

17 17 Dynamic Memory Allocation Operator new int *y; y = new int; *y = 10; float *x = new float [n]; // array Operator delete delete y; delete [] x; // one-dimensional array

18 18 The operator new int *y = new int; *y = 10 or int *y = new int (10) or int *y; y = new int (10)

19 19 One-Dimensional Arrays Float *x = new float [n] addressing the elements: –x[10], x[n-1]

20 20 Exception Handling Using #Include using try and catch float *x; try {x = new float [n];} catch (xalloc) {// enter only when new fails cerr << “out of Memory” << endl; exit (1); } –xalloc exception is thrown by new when unable to allocate memory memory

21 21 Two-dimensional Arrays Char c[7][5] // static allocation Dynamic allocation: char (*c) [5]// number of columns=5 try {c = new char [n][5];} // n is a variable catch (xalloc) { // enter only when new fails cerr << “out of Memory” << endl; exit (1); } Value of n may be determined dynamically

22 22 Two-dimensional Arrays What if number of columns is not known at compile time? Need to construct array dynamically View 2-d array as a 1-d array of rows Each row is created using new Pointers to each row are saved in another 1-d array. X

23 23 Pointer to Pointers template bool make2darray(T ** &x, int rows, int cols) { try { x = new T * [rows]// array of pointers // create memory for each row for (int i = 0, i <rows; i++) x[i] = new int [cols] return true } catch (xalloc) {return false;} }

24 24 Classes Example: define a class currency $2.35 -$64.32 Operations: –set data values –determine components –add two objects –increment the value –output

25 25 Classes enum sign (plus, minus); class Currency { private: sign sgn; unsigned long dollars; unsigned int cents; public: Currency(sign s = plus, unsigned long d = 0, unsigned int c = 0); ~Currency() {} bool Set(sign s, unsigned long d, unsigned int c); bool Set (float a);

26 26 Classes - cont. sign Sign() const {return sgn;} unsigned long Dollars() const {return dollars;} unsigned int Cents () cosnt {return cents;} Currency Add (const Currency& x) const; Currency& Increment (const Currency& x); void Output () const; }

27 27 Classes - cont. void main () { Currency f; currency g(plus, 2, 45), h(minus, 10); Currency *m = new Currency (plus, 8, 12); g.Set(minus, 33, 0); h.Set(78.33); }

28 28 Member Functions //Class constructor Currency::Currency(sign s, unsigned long d, unsigned int c) { if (c > 99) { cerr << “Cents should be < 100” << endl; exit (1);} sgn = s; dollars = d; cents = c; }

29 29 Member Functions - Cont. Bool Currency::Set(sign s, unsigned long d, unsigned int c) { if (c > 99 ) return false; sgn = s; dollars = d; cents = c; return true; }

30 30 Member function -cont Bool Currency::Set (float a) { if (a < 0) {sgn = minus; a = -a;} else sgn = plus; dollars = a; cents = ( a + 0.005 – dollars) * 100; return true; } //00.5 is needed to take care of computer errors when representing float numbers

31 31 Add

32 32 Member function -cont Currency& Currency::Increment(const Currency& x) { *this = Add(x); return *this; } this points to the invoking object *this is the invoking object

33 33 Operator Overloading C++ built-in operators can be overloaded Overloaded operator obeys the precedence, associativity, and number of operands dictated by the built-in operator When an operator is overloaded as a member function, the object associated with the operator is the left-most operand example: X + Y X.operator + (Y) => left-most operand must be an object of the class of which the operator is a member. If that is not the case, instead of using a member operator use a friend operator.

34 34 Operator Overloading enum sign (plus, minus); class Currency { private: sign sgn; unsigned long dollars; unsigned int cents; public: Currency(sign s = plus, unsigned long d = 0, unsigned int c = 0); ~Currency() {} bool Set(sign s, unsigned long d, unsigned int c); bool Set (float a);

35 35 Operator Overloading sign Sign() const {return sgn;} unsigned long Dollars() const {return dollars;} unsigned int Cents () cosnt {return cents;} Currency operator+ (const Currency& x) const; Currency& Increment (const Currency& x); void Output () const; }

36 36 Operator Overloading Currency Currency::operator+ (const Currency& x) const { Currency y; y.amount = amount + x.amount; return y; } Example: Currency A(2, 50), B(minus, 7, 35), C; C = A + B;

37 37 Operator Overloading void Currency :: output() const { if (sgn == minus) cout << ‘-’; cout << ‘$’ << dollars << ‘.’; if (cents < 10) cout << “0”; cout << cents; } Example:Currency X(plus, 3, 50); X.output();

38 38 Operator Overloading Better overload the stream insertion operator <<: cout << X; Note However, cout.operator << X // erroneous the object from which the operator is invoked is not an object of type Currency. ==> operator << can NOT be a member of the class. Can define operator outside the class ==> no access to private members Define it as a friend member.

39 39 New Currency Class class Currency { friend ostream& operator<< (ostream&, const Currency&); public: Currency() …. Unsigned long Dollars() const { if (amount < 0) return (-amount) / 100; else return amount / 100;} …. Private: long amount; }

40 40 Member function -cont ostream& operator<< (ostream& out, const Currency& X) { if (X.sgn == minus) out << ‘-’; out << ‘$’ << x.dollars << ‘.’; if (X.cents < 10) out << “0”; out << X.cents; return out; }

41 41 Friend Functions/Operators A friend function is a function defined outside of the class scope. Note: there is no scope resolution The keyword “friend” is used in the class specification A friend function of a class has access to the private members of the class Inside the function definition, the dot operator is required to access the class data members.

42 42 Classes with Dynamic Data Members Class constructor(s) Class destructor Class copy-constructor Class deep copy function member

43 43 Classes with Dynamic Data Members The following member functions are needed  Class constructor(s)  initialization  allocate space for dynamic data  Invoked automatically when an object is created  Class destructor  free space allocated for dynamic data  Invoked automatically when an object goes out of scope  Class copy-constructor  needed to do deep copying. Invoked automatically in the following situations  Initialization at declaration  An object parameter is passed by value  An object is the function return value  Class deep copy function member: Must be invoked explicitly

44 44 The Date Class Example class Date { public: Date(int, int, int, char* );// Constructor Date(void );// default Constructor Date(const Date& ) // Copy-constructor ~Date( void);// Destructor voidDeepCopy (Date OtherDate); // Deep copy …. void get(int&, int&, int&); private: int month, day, year; char* msg;//pointer to char string };

45 45 Class Constructors Date::Date(void )//default constructor { day = 1; month = 1; year = 1; msg = NULL;//msg points to NULL } Date::Date(int d, int m, int y, char* msgstr) { day = d; month = m; year = y; //Allocate memory for a new string of char msg = new char[strlen(msgstr) + 1]; //copy msgstr into msg strcpy(msg, msgstr); }

46 46 Class Constructors class Date { public: Date(int =1, int =1, int =1, char* =NULL ); //Constructor with default parameters Date(const Date& ) // Copy-constructor ~Date(void );// Destructor voidDeepCopy (Date OtherDate); //Deep copy void get(int&, int&, int&); private: int month, day, year; char* msg;//pointer to char string };

47 47 Class Constructors Example: Date X, Y(10, 5, 1995); Date Z(9, 2, 2002, "Labor Day"); Date A[100]; When declaring an array of objects, the default constructor is used to initialize each object in the array. If no default constructor (and no default parameters), the array objects will NOT be initialized.

48 48 Needed to do deep copying. Invoked automatically in the following situations:  Initialization at declaration  An object parameter is passed by value  An object is a function return value Copy Constructor

49 49 Copy Constructor class ClassName { public: ……… ClassName(const ClassName& SomeObject); private: ……… };  A copy constructor is needed only if some data members are dynamic data  The name of the constructor is the same as the name of the class  The parameter is a reference to an object of the class type.

50 50 Date Copy-Constructor //Implementation of Date copy-constructor Date::Date(const Date& OtherDate) { // copy static data members month = OtherDate.month; day = OtherDate.day; year = OtherDate.year; //copy dynamic data member msg = new char[strlen(OtherDate.msg)+1]; strcpy(msg, OtherDate.msg); } Example: Date X(9, 2, 2002, "Labor Day"); Date Y= X;// Initialization at declaration

51 51 Class Destructor Date::~Date(void) { // De-allocate data pointed to by msg. delete [ ] msg; } Invoked automatically when an object gets out of scope Needed when a class uses dynamic data members to de- allocate memory

52 52 Deep vs. Shallow Copying of Dynamic Data Members What happens when the following function is executed? #include "date.h" int main( void) { DateD1(10,10,2002, “Al Birth Day”); DateD2(2, 5, 1999, “Jane Birth Day”); D1 = D2;// Assignment Requires copying // D2 into D1 return 0; }

53 53 Deep vs. Shallow Copying of Dynamic Data Members void Date::DeepCopy(const Date& X) { // Copy static data members day = X.day;month = X.month; year = X.year; //Copy dynamic data members delete [] msg;// deallocate the original string msg = new char[strlen(X.msg) + 1]; // allocate space for new string strcpy(msg, X.msg);// copy the X.msg in msg } Example: DateD1(10,10,1772, “Al Birth Day”); DateD2(2, 5, 1999, “Jane Birth Day ”); D1.DeepCopy( D2);// Assignment

54 54 Overloading the = operator with deep copy class Date { public: Date(int=1, int=1, int=1, char* = 0 ); //Constructor Date(const Date& ) // Copy-constructor ~Date( );// Destructor void operator = (Date OtherDate); // deep copy assignment void get(int&, int&, int&); private: int month, day; year; char* msg;//pointer to char string };

55 55 Overloading the = operator with deep copy void Date::operator = (Date X) { // Copy static data members day = X.day;month = X.month; year = X.year; //Copy dynamic data members delete [] msg;// deallocate the original string msg = new char[strlen(X.msg) + 1]; // space for new string strcpy(msg, X.msg);// copy the X.msg in msg }

56 56 Example: DateD1(10,10,1772, “Al Birth”); DateD2(2, 5, 1999, “Jane Birth”); D1 = D2;

57 57 More on C++ preprocessor –to ensure that compilation is done only once #ifndef Preprocessor_Identifier #define Preprocessor_Identifier class definition #endif

58 58 Testing To expose the presence of errors test data test set designing test data –black box method –white box method

59 59 White box methods statement coverage decision coverage clause coverage execution path coverage

60 60 Debugging suggestions logical reasoning program trace make sure the correction does not introduce new errors use incremental testing and debugging

61 61 End of Chapter 1


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