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How do you find the volume of a cone?
LearnZillion Notes: --This is your hook. Start with a question to draw the student in. We want that student saying, “huh, how do you do X?” Try to be specific. For example, the hook could be “How do you know if 2/3 is greater than 5/8?” rather than something more generic such as “How do you compare fractions?” --You can fill in an example using the blue text or you can delete that text box and include some other image that explains what you’re talking about.
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LearnZillion Notes: --This is our lesson objective. Keep it as short and student-friendly as possible. Put what they will learn in green and then how they’ll learn it in blue. For example, “In this lesson you will learn how to compare fractions with different denominators by using a number line.”
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Cylinder Volume = Base x height V = πr2h LearnZillion Notes:
We already know how to find the volume of a right prism by multiplying the base area (B) times the height (h): V=Bh. Represent visually. (6.G.2)
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Cylinder: V = πr2h Cone: V= ??? LearnZillion Notes:
So if we know that the volume of a cylinder is V= πr2h. But what if we have a cone that has the same height and radius as this cylinder? What will the volume of this cone be? Some people might take a guess that it is half the volume or maybe a little less. Let’s see if we can figure it out.
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LearnZillion Notes: we can now apply the idea that V=Bh to solve our original problem. Here we have a cylinder with radius 2 and height 7cm.
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Volume of Cone = 1 3 Volume of Cylinder
V = 1 3 πr2h
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V = 1 3 πr2h V = 1 3 π(2cm)2 x9cm V = 12πcm3
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V = πr2h V = π(2cm)2 x 6cm V = 24πcm3 V= 1 3 πr2h V = 8π cm3
Students often use the circle’s circumference to find the area of the base of the cylinder rather than the circle’s area. Don’t do that. For example, in this case we have a cylinder with radius 5cm and height 9cm. It would be easy to say that volume is base times height or 2 pi r h if we mistakenly substitute circumference for the base. This would give us 90pi cm^2 which is incorrect. Always remember to use pi r squared for the area of the base and not the circumference. This will give the correct answer. In this case, the answer is 225 pi cm^3
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LearnZillion Notes: --This is the lesson conclusion. On this slide you’ll change your original lesson objective to past tense and explain what the student has just learned. You can retype it here or you can delete the text on this slide and then just copy and paste the text box from the original Lesson Objective slide and then edit it to make it past tense!
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V = 1 3 πr2h V = 1 3 π(3cm)2 x10cm V = 30πcm3 LearnZillion Notes:
--The “Guided Practice” should include 1 practice problem that targets the skill that was used in the Core Lesson. Use the same vocabulary and process you used in the original lesson to solve this problem. You’ll be making a video in which you solve this question using your tablet and pen, so all you need to do is write the question on this slide.
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V = 1 3 πr2h V = 1 3 π(4cm)2x 12cm V = 64π cm3 LearnZillion Notes:
--The “Guided Practice” should include 1 practice problem that targets the skill that was used in the Core Lesson. Use the same vocabulary and process you used in the original lesson to solve this problem. You’ll be making a video in which you solve this question using your tablet and pen, so all you need to do is write the question on this slide.
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LearnZillion Notes:
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Use measurement and geometrical shapes to demonstrate the relationship between the volume of a cone and volume of a similar cylinder. Record your measurements and calculate the percent error in your measurements assuming the actual relationship is Vcone = 1 3 Vcylinder LearnZillion Notes:
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LearnZillion Notes: --”Quick Quiz” is an easy way to check for student understanding at the end of a lesson. On this slide, you’ll simply display 2 problems that are similar to the previous examples. That’s it! You won’t be recording a video of this slide and when teachers download the slides, they’ll direct their students through the example on their own so you don’t need to show an answer to the question.
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