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Arithmetic Sequences & Series. Arithmetic Sequence: The difference between consecutive terms is constant (or the same). The constant difference is also.

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Presentation on theme: "Arithmetic Sequences & Series. Arithmetic Sequence: The difference between consecutive terms is constant (or the same). The constant difference is also."— Presentation transcript:

1 Arithmetic Sequences & Series

2 Arithmetic Sequence: The difference between consecutive terms is constant (or the same). The constant difference is also known as the common difference (d). (It’s also that number that you are adding everytime!)

3 Example: Decide whether each sequence is arithmetic. -10,-6,-2,0,2,6,10,… -10,-6,-2,0,2,6,10,… -6--10=4 -6--10=4 -2--6=4 -2--6=4 0--2=2 0--2=2 2-0=2 2-0=2 6-2=4 6-2=4 10-6=4 10-6=4 Not arithmetic (because the differences are not the same) 5,11,17,23,29,… 5,11,17,23,29,… 11-5=6 11-5=6 17-11=6 17-11=6 23-17=6 23-17=6 29-23=6 29-23=6 Arithmetic (common difference is 6) Arithmetic (common difference is 6)

4 Rule for an Arithmetic Sequence a n =a 1 +(n-1)d

5 Example: Write a rule for the nth term of the sequence 32,47,62,77,…. Then, find a 12. The is a common difference where d=15, therefore the sequence is arithmetic. The is a common difference where d=15, therefore the sequence is arithmetic. Use a n =a 1 +(n-1)d Use a n =a 1 +(n-1)d a n =32+(n-1)(15) a n =32+(n-1)(15) a n =32+15n-15 a n =32+15n-15 a n =15n+17 a n =15n+17 a 12 =15(12) + 17=197

6 Example: One term of an arithmetic sequence is a 8 =50. The common difference is 0.25. Write a rule for the nth term. Use an=a1+(n-1)d to find the 1st term! a8=a1+(8-1)(.25) 50=a1+(7)(.25) 50=a1+1.75 48.25=a1 * Now, use an=a1+(n-1)d to find the rule. an=48.25+(n-1)(.25) an=48.25+.25n-.25 an=48+.25n

7 Now graph a n =48+.25n. Remember to graph the ordered pairs of the form (n,a n ) Remember to graph the ordered pairs of the form (n,a n ) So, graph the points (1,48.25), (2,48.5), (3,48.75), (4,49), etc. So, graph the points (1,48.25), (2,48.5), (3,48.75), (4,49), etc.

8 Example: Two terms of an arithmetic sequence are a 5 =10 and a 30 =110. Write a rule for the nth term. Begin by finding the distance between the terms Begin by finding the distance between the terms 30 – 5 = 25 AND 110 – 10 = 100 100/25 = 4 so d = 4 a 5 =a 1 +(5-1)d Now solve for a 1 10=a 1 +4*4 a 1 =-6 Now find the rule a n =a 1 +(n-1)d a n =-6+(n-1)(4) a n =-6 + 4n -4 OR a n =4n - 10

9 Example (part 2): using the rule a n =-10+4n, write the value of n for which a n =-2. -2=-10+4n8=4n2=n

10 The 4 th term of an arithmetic sequence is 20 and the 13 th term is 65. Write the first several terms of the sequence 65 - 20 = 45 13 – 4 = 9 45/9 = 5 a n = a 1 + (n-1)d a 13 = a 1 + (13-1)5 65 = a 1 + (12)5 65 = a 1 + 60 5 = a 1

11 Arithmetic Series The sum of the terms in an arithmetic sequence The sum of the terms in an arithmetic sequence The formula to find the sum of a finite arithmetic series is: The formula to find the sum of a finite arithmetic series is: # of terms 1 st Term Last Term

12 Example: Consider the arithmetic series 20+18+16+14+…. Find the sum of the 1 st 25 terms. Find the sum of the 1 st 25 terms. First find the 25th term. First find the 25th term. a 25 =20+(25-1)(-2)=-28 a 25 =20+(25-1)(-2)=-28 So, a 25 = -28 So, a 25 = -28

13 Assignment Worksheet pg 68 and pg 69


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