1. ECEN4503 Random Signals Lecture #1 & 2; 13 & 15 January 2014 n Read Chapter 1 n Read Sections 2.1 - 2.3 n Problems 2.3, 2.8, 2.9, 2.10 (1 ST edition) n Problems 2.9, 2.16, 2.23, 2.24 (2 nd edition) n Quiz #1 on 24 January

2. ECEN4503 Random Signals Lecture #3 17 January 2014 Dr. George Scheets n Read sections 2.4 - 2.6 n Homework: 2.11, 2.13, 2.15, 2.16 (1 st Edition) n Homework: 2.35, 2.39, 2.26, 2.45 (2 nd Edition) n Quiz #1 on 24 January

3. Grading n In Class: Quizzes, Tests, Final Exam Open Book & Open Notes WARNING! Study for them like they’re closed book! n Ungraded Homework: Assigned most every class Not collected Solutions Provided Payoff: Tests & Quizzes

4. Why work the ungraded Homework problems? n An Analogy: Data Com vs. Soccer n Reading text = Reading a book about Soccer n Looking at the problem solutions = watching a scrimmage n Working the problems = practicing or playing in a scrimmage n Quiz = Exhibition Game n Test = Big Game

5. To succeed in this class... n Show some self-discipline!! Important!! For every hour of class...... put in 1-2 hours of your own effort. n PROFESSOR'S LAMENT If you put in the time You should do fine. If you don't, You likely won't.

6. Cheating n Don’t do it! If caught, expect to get an ‘F!’ for the course. n My idol: Judge Isaac Parker U.S. Court: Western District of Arkansas 1875-1896 a.k.a. “Hanging Judge Parker” a.k.a. “Hanging Judge Parker”

7. Why is 4503 Required? n Controls, Communications, IC Design u Random, unpredictable, signals u What voltages are most likely? u What frequencies are most likely? n Another Field? u May help you at Vegas n Important Enough u ABET Requires it for accreditation

8. Probability n Is a number between 0 and 1, inclusive n Quiz or test answer outside this range? u After 1st test, note something is not right!!! u PENALTY WILL ESCALATE!!! Will max out at zero credit for problem on Final Exam.

9. Define Your Events Before Calculating a Probability

10. Probability of Unions n P(a + b) = P(a) + P(b) - P(ab) u If ab = {null set}, a & b are Mutually Exclusive In this case, clearly P(ab) = 0 n Use Venn Diagrams for more complicated expressions u Such as P(a + b + c + d) u Insure each area is counted only once

11. Other Key Theorems to Know n P(a)P(b|a) = P(ab) u Conditional Probability n P(ab) = P(a)P(b) u iff a and b are Statistically Independent n P(b) = P(a 1 b) +... + P(a n b) u Total Probability P( a 1 +...+ a n ) must = 1 a i ∩ a j must be mutually exclusive, i ≠ j n 7) P(a|b)P(b) = P(b|a)P(a) = P(ab) = P(ba) u Baye's Theorem