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Published byLouisa Logan Modified over 9 years ago
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Objective: To determine the internal torque and the associated shear stress for statically indeterminate problems. T A C B L AC L CB L 1)Reaction at A and B. 2)Internal torque at segment AC and CB. 3)Stress at AC and CB. Find,
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Dr. H. Ali Al-Gadhib T AB TATA TBTB TATA T AC T AC = T A T CB TBTB T CB = T B Equation of equilibrium. T B – T + T A = 0 ---------------- A Where T A and T B are reactions at supports. T CB – T + T AC = 0 ---------------- B Equation of equilibrium. Equation A is of better form…
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Dr. H. Ali Al-Gadhib T AC L AC + T CB L CB = 0 ---------------- C Solving equations B & C for the internal torque (T AC and T CB ) and then find reactions and stress.
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Dr. H. Ali Al-Gadhib Example: The solid steel shaft as shown in figure has a diameter of 20 mm. If it is subject to the two torques, determine the reactions at the fixed support A and B.
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Dr. H. Ali Al-Gadhib Solution: Equation of equilibrium.
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Dr. H. Ali Al-Gadhib Compatibility:
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Dr. H. Ali Al-Gadhib Example: The shaft as shown in figure is made from a steel tube, which is bonded to a brass core. If a torque of T = 250 N·m is applied at its end, plot the shear-stress distribution along a radial line of its cross-sectional area. Take G st = 80 GPa, G br = 36 GPa.
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Dr. H. Ali Al-Gadhib Solution: Equilibrium. Compatibility.
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Dr. H. Ali Al-Gadhib Solving Eqs. 1 and 2, we get
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Dr. H. Ali Al-Gadhib
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