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Published byMorris Casey Modified over 9 years ago
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RM->HTR cabling organization pawel de barbaro, apr-18-2006, Agreed on april-20, 2006
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Patch panel math one shelf of patch panel = 8 12-packs of fibers = total of 96 fibers 1 RM = 6 fibers, 1 RBX=4*RM = 24 fibers, 4 RBXes = 4*24 fibers = 96 fibers 6 HTRs = 6*16 fibers = 96 fibers one shelf can handle 4 RBXes=>6 HTRs Basic unit: two 20 deg wedges of HBHE For example: w14+w15 (for mtcc)
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Overall p. panel layout, RBXes organized horizontally, RMs organized vertically RM1 RM2 RM1 RM3 RM4 RM3 RM4 RM1 RM2 RM1 RM2 RM3 RM4 RM3 RM4 HB14 HE14 HB15 HE15 8*12- packs
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Resulting HTR layout RM1 RM2 RM1 RM3 RM4 RM3 RM4 RM1 RM2 RM1 RM2 RM3 RM4 RM3 RM4 HTR0 HTR1 HTR2 HTR0 HTR1 HTR2 HBHE14HBHE15
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One patch panel: 16 six-packs, good for 4 RBXes-> 6 HTRs HB14 HE14 HB15 HE15 PP1 htr0 htr1 htr2 w14w15 12-pack 8 fibers, half-HTR
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4 six-packs (2 twelve-packs), good for 1 RBX, used by HB14 RM1 RM2 RM3 RM4 f7, f6 f5, f4 f3, f2 htr0-bot htr1-top HB 14 htr0-top htr1-bot
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4 six-packs, good for 1 RBX, to be used by HE14 RM1 RM2 RM3 RM4 f2, f3 f4, f5 f6, f7 htr1-bot htr2-bot HE 14 htr2-top htr1-top
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Left half, viewed from front of patch panel numbers are RM-fiber numbers (2-7) HB14 HE14 rm1 6 4 2 2 4 6 7 5 3 3 5 7 rm2 6 4 2 2 4 6 7 5 3 3 5 7 rm3 6 4 2 2 4 6 7 5 3 3 5 7 rm4 6 4 2 2 4 6 7 5 3 3 5 7
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it goes into HTRs in the following way (also viewed from the front) HTR0 HTR1 HTR2 top 1 5 1 5 1 5 2 6 2 6 2 6 3 7 3 7 3 7 4 8 4 8 4 8 bot 1 5 1 5 1 5 2 6 2 6 2 6 3 7 3 7 3 7 4 8 4 8 4 8 HTR fiber Numbers shown HTR0: HB only HTR1: HB/HE HTR2: HE only
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Layout of RBXes in patch panels green barrack (mtcc) HB14 HE14 HB15 HE15 HB16 HE16 HB17 HE17 HB5 HB6 HB7 HB8 HO2a HO2b HO1 HO0 PP1 PP2 PP3 PP4 PP5 CU-hb CU-he CU-ho 6HTRs 8HTRs (HB, HB/HE) 6HTRs 2HTRs: HB(8f)+HE(8f)+HO(4f)
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Jim’s rohlf layout http://cmsdoc.cern.ch/cms/HCAL/document/904/survival/mapping/HB_HE/http://cmsdoc.cern.ch/cms/HCAL/document/904/survival/mapping/HB_HE/hb_he_map_v5.htm
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