1. Inferences from sample data Confidence Intervals Hypothesis Testing Regression Model

2. Confidence Intervals How well does the xbar represent the true population mean µ ? Can use CIs to determine “how close” we are to the true mean General form of a confidence interval –sample statistic ± (multiplier based on confidence level) x (standard error of statistic) –sampling distribution based on central limit theorem

3. Confidence Interval for Mean General expression: xbar ± t (alpha/2, df) x s/(square root of n) student t distribution standard error (n = sample size) margin of error -- how close we are likely (based on confidence level) to be to population parameter confidence level -- how confident we are that population parameter will be in our interval -- 95 % means alpha is.05.

4. A Confidence Interval Example: Suppose xbar = 100, s = 5 and n = 25. Construct a 95% confidence interval and interpret the interval. 100 ± t (.025,24) x 5 / (square root of 25) 100 ± 2.064 x 1 (97.94, 102.64) We are 95% confident that the true mean is in our interval of (about) 98 to 103.

5. .100.050.025.010.005 t df

6. Confidence Interval Questions : 1. If we took another sample, would we get the same confidence interval ? 2. How does the confidence level relate to the margin of error ? 3. What can be done to reduce the margin of error ?

7. Conceptual view of confidence intervals:

8. CONFIDENCE(alpha,standard_dev,size) Alpha is the significance level used to compute the confidence level. The confidence level equals 100*(1 - alpha)%, or in other words, an alpha of 0.05 indicates a 95 percent confidence level. Standard_dev is the population standard deviation for the data range and is assumed to be known. Size is the sample size. If we assume alpha equals 0.05, we need to calculate the area under the standard normal curve that equals (1 - alpha), or 95 percent. This value is ± 1.96. The confidence interval is therefore:

9. Example Suppose we observe that, in our sample of 50 commuters, the average length of travel to work is 30 minutes with a population standard deviation of 2.5. With alpha =.05, CONFIDENCE(.05, 2.5, 50) returns 0.69291. The corresponding confidence interval is then 30 ± 0.69291 = approximately [29.3, 30.7]. For any population mean, μ0, in this interval, the probability of obtaining a sample mean further from μ0 than 30 is more than 0.05. Likewise, for any population mean, μ0, outside this interval, the probability of obtaining a sample mean further from μ0 than 30 is less than 0.05.

10. Hypothesis Testing A study and assessment of data to examine two hypotheses: null and alternative. Six step process 1. state hypotheses, decision making alternatives and consequences of wrong decisions 2. select the appropriate test statistic 3. sketch sampling distribution and identify rejection region 4. collect data, compute statistics 5. test the null hypothesis and state conclusions 6. state managerial decision

11. Hypothesis test example: Our engineering staff claims we will obtain an average catapult launch of more than 110 inches. We will not market the catapult unless this is true. 1. state hypotheses Ho = ‘statement of no effect’ Ho = mean of launch is less than or equal to 110 inches Null action = don’t market. Ha = ‘there is an effect or difference’ Ha = mean launch is greater than 110 inches Alternative action = market catapult; ‘launch’ marketing campaign.

12. Type 1 and Type 2 Errors

13. With sample data, always a chance to make incorrect decisions setting significance level. For type 1 error, the alpha is the maximum risk we are willing to take for this type of error. Rules of thumb from Harvey Brightman: 1. Type 1 error costly and type 2 is not -- set alpha low --.05 or less 2. Type 2 error costly and type 1 is not -- set alpha higher -- perhaps.25 or above 3. Both errors costly -- set alpha low and increase sample size We are going to set alpha =.01

14. 2. Select test statistic For large samples, use Z and for small samples use t Z = xbar - mu -------------------------------- sigma / (square root of n) -- for the t test statistic, substitute s for sigma

15. 3. Sketch sampling distribution and rejection region t = 2.5395.01,19 =TINV(2*0.01,19)

16. TINV TINV(probability,degrees_freedom) Probability is the probability associated with the two-tailed Student's t- distribution. Degrees_freedom is the number of degrees of freedom with which to characterize the distribution. Remarks A one-tailed t-value can be returned by replacing probability with 2*probability. For a probability of 0.05 and degrees of freedom of 10, the two-tailed value is calculated with TINV(0.05,10), which returns 2.28139. The one-tailed value for the same probability and degrees of freedom can be calculated with TINV(2*0.05,10), which returns 1.812462. EXCEL

17. 4. Collect data and compute statistics Let x bar = 115, s = 8 and n = 20 115 - 110 t* = ------------ 8 / (square root of 20) t* = 2.795 5. Statistical decision Since t * is in the rejection region, we reject the null and accept the alternative hypothesis.

18. Observations from Two Populations

19. Summary Statistics for the Two Groups

20. Using the t test statistic to test for a difference in the two means: Hypothesis test: Test statistic for hypothesis test on difference in two means

21. In our case: n1 = 20 s 1 = 6.15 n2 = 20 s 2 = 6.98 s = 9.56 t* = 17.9 / 3.02 = 5.93 Comparing to a t  at.05,18 = 1.734 Would conclude statistically different the Numbers

22. EXCEL Example

23. Tools | Data Analysis | =TINV(0.05,16) =TINV(0.05*2,16)

24. 24 Linear Regression Model Linear regression form: systematic variation in time series regression function (linear function of time) error term represents unsystematic or random variation

25. 25 Tools | Data Analysis | Regression

26. 26 =375.17+92.6255*C3 note: column C is time period Our regression model