Download presentation
Presentation is loading. Please wait.
Published byTimothy Bishop Modified over 9 years ago
1
Solving Absolute Value Equations & Inequalities Solving Absolute Value Equations & Inequalities Isolate the absolute value
2
Absolute Value (of x) Symbol lxl The distance x is from 0 on the number line. Always positive Ex: l-3l=3 -4 -3 -2 -1 0 1 2
3
Ex: x = 5 What are the possible values of x? x = 5 or x = -5
4
To solve an absolute value equation: ax+b = c, (where c>0) To solve, set up 2 new equations, then solve each equation. ax+b = c or ax+b = -c ** make sure the absolute value is by itself before you split to solve.
5
Ex: Solve 6x-3 = 15 6x-3 = 15 or 6x-3 = -15
6
Ex: Solve 6x-3 = 15 6x-3 = 15 or 6x-3 = -15 6x = 18 or 6x = -12 x = 3 or x = -2 * Plug in answers to check your solutions!
7
Ex: Solve 2x + 7 -3 = 8 Get the abs. value part by itself first! 2x+7 = 11 Now split into 2 parts. 2x+7 = 11 or 2x+7 = -11.
8
Ex: Solve 2x + 7 -3 = 8 Get the abs. value part by itself first! 2x+7 = 11 Now split into 2 parts. 2x+7 = 11 or 2x+7 = -11 2x = 4 or 2x = -18 x = 2 or x = -9 Check the solutions.
9
Try this one:
10
Divide by 3
11
Next example:
12
Solve this example: -2 { } But they do not check
13
Last one:
14
Last one: be sure to negate the entire other side!
15
Last one: 4x = 4 X = 1
16
Hand this one in
17
Answer: 2x = -16 X = -8 BOTH ANSWERS CHECK.
18
Solving Absolute Value Inequalities 1. ax+b 0 Becomes an “and” problem Changes to: –c<ax+b<c 2. ax+b > c, where c>0 Becomes an “or” problem Changes to: ax+b>c or ax+b<-c
19
Interval notation: 2<x<9 (2,9) x 2 [-1,5] Note that
20
When it’s less than It’s and “and”
21
Ex: Solve & graph. Becomes an “and” problem -3 7 8 [-3,7.5] Interval notation:
22
Greater than Is an or
23
Solve & graph. Get absolute value by itself first. Becomes an “or” problem -2 3 4
24
Try this one:
25
Now decide that it is an “and” graph!
26
answer:
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.