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Published byLinette Terry Modified over 9 years ago
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Forces on Inclined Planes Unit 3, Presentation 3
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Inclined Planes Inclined planes create unusual complications because the standard x-y plane is no longer the only direction of motion The x-y plane must be rotated to most easily solve the problems.
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An Inclined Plane Example Problem Calculate the time it takes for the following block to slide down the inclined plane: 5 kg 40° 10 m k =0.30 Assume that the block starts from rest.
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Inclined Plane Example Problem First, draw a free body diagram for the block: mg FnFn frictionNote that, right now, only one of our forces is in the standard x-y plane (mg). If we re-orient the x-y plane with the positive x-axis along friction and the positive y-axis along the normal force, then we only have to break mg down into components: x y xy
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Inclined Plane Example Problem Now, lets consider the forces in the x and y directions: x - directiony - direction Friction (negative) x-component of weight: Normal Force y-component of weight:
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Inclined Plane Example Problem Now, lets set up separate equations for the x and y directions using Newton’s 2 nd Law: x - directiony - direction Using substitution Lets solve for acceleration in the x-direction and use that to find time using the kinematic equations.
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Inclined Plane Example Problem Now we need to find the distance traveled using trigonometry: 10 m 40° x
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Inclined Plane Example Problem Now, use the big kinematic equation to find time.
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Another Inclined Plane Example Problem Suppose a block with a mass of 2.50 kg is resting on a ramp. If the coefficient of static friction between the block and ramp is 0.350, what maximum angle can the ramp make with the horizontal before the block begins to slip down? 2.50 kg s =0.350
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Another Inclined Plane Example First, draw a free body diagram for the block: mg FnFn friction x-direction y-direction Friction (negative) x-component of weight Normal Force y-component of weight
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Another Inclined Plane Example Now, use Newton’s Second Law in both directions: x-direction y-direction When it just begins to move, acceleration just begins to increase above zero. To find the critical point, set a=0. Use Substitution Note that both m and g cancelled out of the problem!
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